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Lady bird [3.3K]
3 years ago
6

There are 24 cookies for the price of 3.50 what is the price of one cookie

Mathematics
1 answer:
Veronika [31]3 years ago
8 0

Answer:

Tu divises 3.50$ par 24 cookies donc environ 14 centimes

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An element with mass 670 grams decays by 27.3% per minute. How much of the element is remaining after 9 minutes, to the nearest
ArbitrLikvidat [17]
There will be 38 grams remaining.

The equation would be of the form
y = a(1+r)ˣ, where a is the initial value, r is the rate as a decimal number, and x is the amount of time.  Using our values from the problem, we have:

y = 670(1-0.273)^9 = 670(0.727)^9 = 38
6 0
3 years ago
Read 2 more answers
A cylindrical container has a volume of 36 cm³. Another container made out of the same material is similar to the first containe
USPshnik [31]
I hope this helps you



Volume = pi.r^2.h


36= pi.r^2.h



Volume =pi.r^2.3/4h


Volume =pi.r^2.h.3/4


Volume =36.3/4


Volume =9.3


Volume =27

3 0
3 years ago
Read 2 more answers
Pls help will mark brainliest
tatuchka [14]

Answer: subtract 10

Step-by-step explanation: 25 - 10 =15

5 0
3 years ago
un solar tiene forma de 3/4 de círculo unido con un triángulo rectángulo , En este solar va a ser utilizado para sembrar clavele
Stolb23 [73]

Answer:

$1092671.191

Step-by-step explanation:

<u>Cálculo de Areas</u>

El área de un círculo de radio r se obtiene con la fórmula:

A_c=\pi r^2

El área de un triángulo de base b y altura h, perpendicular a la base es:

A_t=\frac{bh}{2}

Si el triángulo es rectángulo, b y h son los catetos

El solar tiene una forma tal como se ilustra en la figura anexa. Para averiguar el costo del abono y del techo, debe calcularse primero el área total a cultivar. Primero se determina el área de 3/4 de círculo de radio 5.9 metros

A_c=\frac{3}{4}\pi r^2

A_c=\frac{3}{4}\pi (5.9)^2

A_c=82.0191302\ m^2

Por su parte, el triángulo mostrado, tiene ambos catetos iguales al radio de círculo, por lo que su área será

A_t=\frac{r^2}{2}

A_t=\frac{(5.9)^2}{2}

A_t=17.405\ m^2

El área total del solar es la suma de ambas:

A_s=82.0191302\ m^2+17.405\ m^2

A_s=99.4241302\ m^2

El metro cuadrado de abono cuesta $8016. El costo de abono es

C_a=99.4241302\ m^2*8016=\$796983.8277

El metro cuadrado de techo cuesta $2974. El costo del techo es

C_t=99.4241302\ m^2*2974=\$295687.3632

El costo total es la suma de los dos anteriores:

Total=\$796983.8277+\$295687.3632

Total=\$1092671.191

El valor total a intervenir para la adecuación del solar es $1092671.191

7 0
3 years ago
Use addition to solve the linear system of equations. 
Ipatiy [6.2K]
I'm not quite sure if this is what you need, but I am going to solve these equations by elimination. x= 8/17 and y = 11/17 (8/17, 11/17). 
6 0
3 years ago
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