Answer:
Explanation:
If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.
mgh = ½mv²
v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s
However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy
mgh = ½mv² + ½Iω²
mgh = ½mv² + ½(½mR²)(v/R)²
2gh = v² + ½v²
2gh = 3v²/2
v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s
Answer
Magma is less dense compared to the surrounding rock.
the overlying rock creates pressure which forces the magma to be directed upward.
Explanation:
at high temperatures the magma is liquid form with the high energy which causes the formation of bonds and the pressure build up creates the increase channeling of the liquid.as the temperature decreases the magma moves into the surface
Answer:
Option (D) is correct.
Explanation:
The balloon lands horizontally at a distance of 420 m from a point where it as released.
Velocity of air balloon along +X axis =10 m/s
velocity of ball=4 m/s along + X axis
the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s
time taken= 30 s
The distance traveled is given by d= v t
d= 14 (30)
d= 420 m
Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.
Answer:
6.02 radian
Explanation:
At 12 noon position is zero radian on Monday
at 12 midnight the position is π/2
at 11 am position on Tuesday is 2π/24 x 23 ( after 23 hours ) = 6..02 radian.
Answer:
= 1220 nm
= 1.22 μm
Explanation:
given data:
wavelength 
distance of screen from slits D = 3 m
1st order bright fringe is 4.84 mm
condition for 1 st bright is
---( 1)
and
= 0.0924 degrees
plug theta value in equation 1 we get
condition for 1 st dark fringe
= 2λ since from eq (1)
= 1220 nm
= 1.22 μm
