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luda_lava [24]
3 years ago
14

How would you go about separating the components of a mixture of sand, gravel, salt and iron filings

Physics
1 answer:
larisa86 [58]3 years ago
4 0

Pour the entire components into water.

First the iron filings can be separated using a magnet as iron is a magnetic element.

By pouring the mixture into water, it allows the salt to dissolve in the water, while the sand will not.

Next we can run this solution through a filtration device to separate the sand from the water.

Now all that's left is to let the water evaporate so that the salt will be exposed that dissolved into the water.

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A 0.10-kilogram piece of modeling clay is tossed
viva [34]

a) The initial speed of the clay is 30 m/s

b) The final velocity of the block increases (40 m/s)

Explanation:

a)

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces (=no friction), the total momentum of the clay + block system is conserved before and after the collision. Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 0.10 kg is the mass of the clay

u_1 is the initial velocity of the clay

m_2 = 0.10 kg is the mass of the wood block

u_2 = 0 is the initial velocity of the wood block (at rest)

v = 15 m/s is the final combined velocity of the clay+block after the collision

Re-arranging the equation, we can find u_1, the speed at which the clay was tossed:

u_1 = \frac{(m_1+m_2)v-m_2 u_2}{m_1}=\frac{(0.10+0.10)(15)-0}{0.10}=30 m/s

b)

In this second case, the clay is replaced by a bouncy ball, which rebounds back after the collision, instead of sticking with the block.

In this second case, the law of conservation of momentum becomes:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2  

where

m_1 = 0.10 kg is the mass of the ball

u_1 = 30 m/s is the initial velocity of the ball

m_2 = 0.10 kg is the mass of the wood block

u_2 = 0 is the initial velocity of the wood block (at rest)

v_1 = -10 m/s is the velocity of the bouncing ball after the collision (negative because it goes backward)

v_2 is the velocity of the block after the collision

Solving for v_2, we find the final velocity of the block:

v_2 = \frac{m_1 u_1 - m_1 v_1}{m_2}=\frac{(0.10)(30)-(0.10)(-10)}{0.10}=40 m/s

As we can see, the final velocity of the block has increased. The reason for that is that, as the ball bounces back, part of the total momentum is "carried away" by the ball in the backward direction, and since the total momentum must remain constant, this means that the momentum carried by the block in the forward direction must be larger than the previous situation.

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

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#LearnwithBrainly

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Answer: A

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Lunar eclipses work the same way in a different order: Moon, Earth and Sun all on a line. In this case the Earth's shadow hides the Moon from view.

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