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pickupchik [31]
3 years ago
5

Describe a good and safe relationship​

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

Many people rush into relationships, whether it be romantic or friendly. No matter the kind of relationship, the number one thing you want to make sure you have is boundaries. When you get to know someone, you have to make sure they respect your beliefs, your boundaries, and won't peer pressure you into doing anything. You also want to make sure the person you are getting to know is getting to know you for you and not anything else. It has been proven that the more happy relationships and healthy relationships we have, the longer we live. But it also works the other way around. That's why we have to make sure we surround ourselves with the right kinds of people otherwise, we'll just end up getting hurt. It's very common for people to be influenced by outside forces and, therefore, hurt us and turn around and instead of being our loved ones, they're our enemies. That's why we have to make sure we choose the right kinds of people.

Step-by-step explanation:

I hope this helps :)

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

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Murrr4er [49]

Answer:

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Step-by-step explanation:

need to find the halfway point (average) between -0.75 and 0.25 (same as 1/4)

To get average, add them together: (-0.75) + (0.25) = -0.5, divide by two since there are two numbers, to get average -0.25

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Step-by-step explanation:

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