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Brilliant_brown [7]
2 years ago
13

What advantage does a heterogeneous catalyst provide over a homogeneous catalyst in industrial processes?

Chemistry
1 answer:
irga5000 [103]2 years ago
8 0
A heterogeneous catalyst can be easily separated from reactants.
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What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t
const2013 [10]

Answer:

C = 0.08M

Explanation:

molar mass of AlCl3

Al =27

Cl = 35.5

27+3(35.5) =133.5g/mol

n= mass/Molar mass

n =CV

CV = mass/molar mass

C x 500 x 10^-³ = 5/133.5

C x 500 x 10^-³ = 0.04

C = 0.04/500 x 10^-³

C = 0.08M

4 0
3 years ago
Question 25 of 33
Dafna11 [192]

Answer:

A) It tends to increase from top to bottom of a group

6 0
2 years ago
What are two chemical properties of chromium? Please?
melomori [17]

Chromium is a fairly active metal. It does not react with water, but reacts with most acids. It combines with oxygen at room temperature to form chromium oxide (Cr 2 O 3 ). Chromium oxide forms a thin layer on the surface of the metal, protecting it from further corrosion (rusting).  


8 0
3 years ago
Read 2 more answers
Given that the density of air is 14.4, then the vapour of sulphur IV oxide is A. 16 B. 32 C. 64 D. 128
Arisa [49]

Answer:

32

Explanation:

The vapour density of a gas is the number of times a given volume of gas or vapour is as heavy as the same volume of hydrogen at a particular temperature and pressure.

Vapour density = 2 × relative molecular mass of the gas or vapour

Relative molecular mass of SO2 = 32 + 2(16) = 64

Hence;

Vapour density of SO2 = 64/2

Vapour density of SO2 = 32

6 0
2 years ago
The area of a telescope lens is 7903 rnrn2 {a) What is the area in square feet (ft2)? (b) If it takes a technician 45 s to polis
LekaFEV [45]

Answer:

Area is 0.08504ft^{2} and 2.6\times 10^{3}s are needed for polishing

Explanation:

(a) ft is unit of F.P.S system whether mm is unit of M.K.S system.

According to unit conversion, 1mm=0.00328ft

So, 1mm^{2}=(0.00328)^{2}ft^{2}=1.076\times 10^{-5}ft^{2}

hence, 7903mm^{2}=7903\times 1.076\times 10^{-5}ft^{2}=0.08504ft^{2}

So, area of telescope lens is 0.08504ft^{2}

(b)135mm^{2} are polished in 45s

So, 7903mm^{2} are polished in \frac{45\times 7903}{135}s or 2.6\times 10^{3}s

5 0
2 years ago
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