Question

Determine whether each compound is soluble or insoluble. If the compound is soluble, list the ions present in solution. AgNO3 Pb(C2H3O2)2 KNO3 (NH4)2S

Answer 1

Answer:

AgNO3 is soluble dissolves in water to give the Ag+ ion and the NO3- ion

Pb(C2H3O2)2 is soluble in water to give the Pb2+ ion and the CH3COO- ion

KNO3 is soluble in water to give K+ ion and the NO3- ion

(NH4)2S is soluble in water to give the NH4+ ion and the S2- ion

Explanation:

This question requires a knowledge of a few solubility rules

All nitrates are soluble in water

All group I salts are soluble in water

All ammonium salts are soluble in water

All ethanoates are soluble in water except silver ethanoate

Answer 2

Answer:

According to the solubility rules:

1. Silver nitrate: AgNO₃ is soluble.

Reason: Nitrates (NO₃⁻) are soluble.

AgNO₃ (aq) → Ag⁺(aq) + NO₃⁻(aq)

Ions present: silver ion (Ag⁺) and nitrate ion (NO₃⁻)

2. Lead(II) acetate: Pb(C₂H₃O₂)₂ is soluble.

Reason: Acetates (C₂H₃O₂⁻) are soluble

Pb(C₂H₃O₂)₂ → Pb²⁺(aq) + 2 CH₃COO⁻(aq)

Ions present: lead(II) ion (Pb²⁺) and two acetate ions (CH₃COO⁻)

3. Potassium nitrate: KNO₃ is soluble.

Reason: Nitrates (NO₃⁻) are soluble and group-1 ions such as K⁺ are soluble.

KNO₃ (aq) → K⁺(aq) + NO₃⁻(aq)

Ions present: potassium ion (K⁺) and nitrate ion (NO₃⁻)

4. Ammonium sulfide: (NH₄)₂S is soluble.

Reason: Ammonium (NH₄⁺) ions are soluble

(NH₄)₂S (aq) → 2 NH₄⁺(aq) + S²⁻(aq)

Ions present: two ammonium ions (NH₄⁺) and sulphide ion (S²⁻)