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Nikolay [14]
3 years ago
7

Pls help what the ratio ?.enter your answer as an integer ​

Chemistry
1 answer:
AveGali [126]3 years ago
6 0

okokokokokokokokokokokokokokokokokok ok vokokokokokokok

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A drop of vinegar ( a weak acid ) is placed on a sample of each of the materials below. Which will show the most active reaction
professor190 [17]

Answer: Option (B) is the correct answer.

Explanation:

Marble is also known as calcium carbonate and its chemical formula is CaCO_{3}.

When it combines with vinegar then it results in the formation of calcium acetate which is a water soluble compound along with the release of carbon dioxide which occurs in the form of bubbles and water.

The reaction is as follows.

    CaCO_{3} + CH_{3}COOH \rightarrow Ca(CH_{3}COOH)_{2} + H_{2}O + CO_{2}

Whereas vinegar being a weak acid will not react with glass, copper and steel.

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3 years ago
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Quicklime is an incredibly caustic substance that has been used during plagues to quickly dissolve diseased corpses. Calcium car
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Answer:I just want points

Explanation:because I need them for future questions

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2 years ago
A thermometer is in a beaker of water. Which statement best explains why the thermometer reading initially increases when LiBr(s
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<span>(4) The dissolving of the LiBr(s) in water is an exothermic process</span>
8 0
3 years ago
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
3 years ago
Which sphere would this be found in?
andre [41]
That is correct…….. i think
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