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krek1111 [17]
3 years ago
6

1J /(g*C), 1*C, 1 J, m=g

Chemistry
1 answer:
Nostrana [21]3 years ago
7 0
You can find the answer on google for this
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PLEASE HELP I WILL GIVE BRAINLY TO CORRECT ANSWER (after I finish test)
riadik2000 [5.3K]

Answer:

i think its 2

Explanation:

because the H2 is seperate from the others it is the only one with a number.

8 0
3 years ago
Hydrogen reacts with 0.771 g of carbon to form 0.90 g of a compound. What is the mass percent of hydrogen in the compound
morpeh [17]
Answer: 14.3%

Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound. 

In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen. 

Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.

Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.

So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%


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4 0
4 years ago
Read 2 more answers
Why do some objects such as windows and doors close in the winter but can be harder to close in the summer?
Elenna [48]
When the temperature rises some materials experience thermal expansion which means they get bigger, so it may make them harder to close because they don't fit as well.
4 0
3 years ago
Read 2 more answers
How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol
Goshia [24]

Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

Given:

Current I = 14.9 A

Faraday constant = 96485 \frac{C}{mole}

Molar mass of Ni = 58.69 \frac{g}{mole}

Mass of Ni = 0.94 g

First find the no. moles in Ni solution,

Moles of Ni = \frac{0.94}{58.69}

                   = 0.02 mol

From the below reaction,

  Ni^{2+}  + 2e ⇆ Ni_{(s)}

Above reaction shows "1 mol of Ni^{2+} requires 2 mol of electron to form 1 mol of Ni_{(s)} "

So for finding charge flow in this reaction we write,

    = 0.02 \times \frac{2  }{1 }  \times 96485 \frac{C}{mol}

Charge flow = 3859.4 C

For finding time of reaction,

  I = \frac{q}{t}

Where q = charge flow

   t = \frac{q}{I}

   t = \frac{3859.4}{14.9}

   t = 259.02 sec

Therefore, time take to deposit Ni is 259.02 sec.

3 0
3 years ago
What is the volume, in liters, of 0.500 mol of c3h3 gas at stp?
jarptica [38.1K]
At STP conditions the volume of  1 mol of any ideal gas will be 22.4L

0.500 mol C3H3 x 22.4L / 1 mol = 11.2 L
8 0
3 years ago
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