you can find it using the equation: potential energy=mass*gravitational acceleration*height.
energy=50kg*9.8N/kg*40m=19600Nm=19600J or 19.6kJ
Sometimes they use 10 instead of 9.8 for the g constant.
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Answer:
The answer is "Option d".
Explanation:
In the given scenario, when a surface is drawn in a magnetic field, the number of magnetic field lines that enter a surface must be equal to the number left because we know that magnetic field lines are always a closed curve hence the number of magnetic field lines that join the surface should match the total left.
Answer:
The focal length for given convex lens = 0.0714 m
Explanation:
Given data
Radius (
) = 12.5 cm
Radius (
) = 16.7 cm
Since the radius of curvature is positive so these are the convex lens.
Now focal length is given by
⇒
=
+ ![\frac{1}{R_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR_%7B2%7D%20%7D)
⇒ Put the values of
and
in the above formula we get,
⇒
=
+ ![\frac{1}{16.7}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B16.7%7D)
⇒
= 0.13988
⇒ f = ![\frac{1}{0.13988}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.13988%7D)
⇒ f = 7.14 cm
⇒ f = 0.0714 m
Thus the focal length for given convex lens = 0.0714 m
Answer:
Explanation:
Left block is on surface with higher inclination so it will go down . If T be tension
For motion of block A ,
net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .
ma = mgsin60 - T - mg cos 60 x .1
10a = 277.13 - T - 16
= 261.13 - T
T = 261.13 - 10a
For motion of block B
T - mg sin30 - mgcos30 x μ = ma
T- 160 - 27.71 = 10 a
261.13 - 10a - 160 - 27.71 = 10a
73.42 = 20a
a = 3.67 ft / s²
common acceleration = 3.67 ft / s²
Answer:
2.82 D
Explanation:
Near point of the person eye is 85 cm that is ![u=85\ cm](https://tex.z-dn.net/?f=u%3D85%5C%20cm)
He wants to see the object at 25 cm so ![v=25\ cm](https://tex.z-dn.net/?f=v%3D25%5C%20cm)
For the lens we know that ![\frac{1}{f}=\frac{1}{v}-\frac{1}{u}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bv%7D-%5Cfrac%7B1%7D%7Bu%7D)
![\frac{1}{f}=\frac{1}{25}-\frac{1}{85}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7B25%7D-%5Cfrac%7B1%7D%7B85%7D)
\frac{1}{f}=0.04-0.01170=0.02823
![f=35.41\ cm](https://tex.z-dn.net/?f=f%3D35.41%5C%20cm)
We know that power of the lens ![P=\frac{1}{f\ in\ meter}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7Bf%5C%20in%5C%20meter%7D)
So ![P=\frac{1}{0.3541}=2.8235\ D](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B0.3541%7D%3D2.8235%5C%20D)