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Anettt [7]
3 years ago
6

A car traveled 1025 km from El Paso to Dallas iin 13.5 hr. What was its average velocity

Physics
1 answer:
JulsSmile [24]3 years ago
5 0
1) 1025km per 13.5hr = 1025km/13.5hr = 75.9 km/hr

2) 400km per 30min = 400km/30min = 13.3 km/min
13.3km/min X (60min per hr) = 13.3km/min(60min/hr) = 800km/hr

3) 45km/hr in 40min = 45km/hr X 40min X (1hr/60min) = 30km.

<span> 4) (30m/s - 10m/s) per 10s = 20m/s/10s = 2ms/s = 2m/s/s = 2m/s^2 </span>
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Read 2 more answers
A block of mass 10.0 kg is pulled to the right along a rough horizontal surface with a constant horizontal force of 20.0 N. The
Yakvenalex [24]

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the magnitude of acceleration will be 1.50m/s^2

Explanation:

To calculate your acceleration, you can use your formula that states that the net force on an object is equal to the mass of the object multiplied by the acceleration of the object. Fnet=ma

if you draw out this situation and label the forces you will have your vector towards the right with a magnitude of 20.0N and then your friction vector will be pointing to the left (in other words, in the negative direction) (opposing the direction of movement) with a magnitude of 5.00N, with the 10.0 kg box in the middle.

The net force will be calculated using F1+F2=Fnet where your F1=20.0N and F2= -5.00N (since it is towards the negative direction).

you will find that Fnet=15.0N

With that, plug in the values you know to calculate the acceleration of the block:

Fnet=ma

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7 0
3 years ago
Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t
zlopas [31]

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y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

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As we know that the wave equation is given as

y = A sin(\omega t - k x + \phi_0)

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k = \frac{2\pi}{\lambda}

k = \frac{2\pi}{2.6}

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also we have

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now we know that at t = 0 and x = 0 wave is at y = 0.19 m

so we have

\phi_0 = \frac{\pi}{2}

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y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

6 0
3 years ago
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