the International System of Units, the fundamental units are: The meter (symbol: m), used to measure length. The kilogram (symbol: kg), used to measure mass. The second (symbol: s), used to measure time. The ampere (symbol: A), used to measure electric current.
Answer:
Explanation:
First of all, well calculate the spring constant k
K = 2Ei/x^2
Where Ei = initial work required
x = initial stretch length
k = 2×7/0.017^2 = 48443J/m^2
Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m
EF = kx^2/2
48443 × 0.053^2/2 = 68J
Work done in stretching additional 3.6cm is equal to
68J-7J = 61J
Highest fluid potential energy: answer A
Because the fluid is pushed upwards and potential energy is function of height. Since point A is the highest, there is the highest potential energy.
highest fluid pressure: answer C
This is because it is at the bottom where you have a hydrostatic pressure component
increasing fluid speed: answer B
This is because the section of the pipe is smaller and in order to have the same fluid flow rate the speed must increase
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
<h3>For smaller balloon:</h3>
- Radius (r) = 3 cm
- Pi (π) = 3.14
- Volume (V) =?
V = 4/3 πr³
V = 4/3 × 3.14 × 3³
<h3>V = 113.04 cm³</h3>
<h3>For larger balloon:</h3>
- Radius (r) = 6 cm
- Pi (π) = 3.14
- Volume (V) =?
V = 4/3 πr³
V = 4/3 × 3.14 × 6³
<h3>V = 904.32 cm³</h3>
Finally, we shall determine how much greater the larger balloon is to the smaller balloon
- Volume of smaller balloon = 113.04 cm³
- Volume of larger balloon = 904.32 cm³
- Greatness =?
Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
<h3>Large = 8 × small </h3>
Therefore, the larger balloon is 8 times greater than the smaller balloon.
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