Answer : The limiting reagent is 
Solution : Given,
Moles of methane = 2.8 moles
Moles of = 5 moles
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of 
So, 5 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Hence, the limiting reagent is
The correct answer to your question is: <span>C) tin (IV) bromide, SnBr₄</span>
Usually, a model is a depiction of a certain entity, never the real thing. In times
past, many, many models look great on paper but are way off!
Hey there !
The answer would be C. 0.68L
Hope this helps !
Balanced equation :
1 CaCO3(s) = 1 CaO(s) + 1 CO2(g)
hope this helps!
