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2 years ago

What is the experimental probability for the lowest frequency? 3/18 4/18 18/4 18/3

Mathematics

1 answer:

elena55 [62]2 years ago

5 0

Answer:

18/3

Step-by-step explanation:

Took the test

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Can anyone help please? No links cause I can’t see them.

tamaranim1 [39]

Answer:

Step-by-step explanation:

you have a right triangle with the hypotenuse of 41 and another side of 40

a= $\sqrt{41^2-40^2}$ = $\sqrt{1681-1600}$ = $\sqrt{81}$

a=9

5 0

2 years ago

Do u just plot the numbers on the graph like (1,26)???

kvv77 [185]

Answer:

Yes

Step-by-step explanation:

Make sure you plot each number on the right axis. :)

4 0

2 years ago

The distance from the Earth to the Sun is approximately 90,000,000 miles, which can be written as 9 × 10a miles, where a = . The

andrey2020 [161]

10*a = 10000000

a = 1000000, one million

5*10*b = 500000000

b = 10000000, ten million

About ten times.

7 0

3 years ago

Read 2 more answers

Simplify 3a + 4b + 5c + (-2a) + b

ad-work [718]

Answer:

 a + 5b + 5c

Step-by-step explanation:

here's your solution

=> 3a + 4b + 5c +(-2a) + b

=> solve for like term

=> 3a - 2a + 4b + b + 5c

=> a + 5b + 5c

hope it helps

7 0

2 years ago

Read 2 more answers

A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find

Ratling [72]

Answer:

Area of the garden:

$\begin{equation*} 398.93\text{ ft}^2 \end{equation*}$

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

$r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}$

Let's now go ahead and determine the area of the semicircle using the below formula;

$A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2$

Let's also determine the area of the rectangle;

$A_r=l*w=23*14=322\text{ ft}^2$

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

$\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}$

Therefore, the area of the garden is 398.93 ft^2

8 0

8 months ago