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Dafna1 [17]
3 years ago
7

The concepts in this problem are similar to those in Multiple-Concept Example 4, except that the force doing the work in this pr

oblem is the tension in the cable. A rescue helicopter lifts a 81.7-kg person straight up by means of a cable. The person has an upward acceleration of 0.729 m/s2 and is lifted from rest through a distance of 7.86 m. (a) What is the tension in the cable
Physics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

Explanation:

Given that:

distance (z) = 7.86 m

mass of the person = 81.7 kg

Acceleration (a) = 0.729 m/s²

By using Newton's second law along the vertical axis:

T - mg = ma\\ \\ T = ma + mg \\ \\  T = m(a+g) \\ \\

T = 81.7 (0.729 +9.8)

T = 860.22 N

The work done now is:

W_T = T\times z \\ \\

W_T = 860.22 \times 7.86

\mathbf{W_T =6761.3292\ N}

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Answer:

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Applying the Law of Conservation of Energy

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Here, total energy is the sum of kinetic energy and potential energy

K.E_{i} + P.E_{i} = K.E_{f} + P.E_{f}       (a)

When banana is at height h, it has

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       K.E_{f}  = 1/2mv^{2}    and   P.E_{f}  = 0

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                                      mgh = 1/2mv^{2}

<em>cutting 'm' from both sides</em>

<em>                                           </em>gh = 1/2v^{2}

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h=39.72 m

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\Delta P.E.=m\times g\times \Delta h

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