41kg object that is moving east at 5 m s
Answer:
The mass of the banana is m and it is at height h.
Applying the Law of Conservation of Energy
Total Energy before fall = Total Energy after fall
=
Here, total energy is the sum of kinetic energy and potential energy
+
=
+
(a)
When banana is at height h, it has
= 0 and
= mgh
and when it reaches the river, it has
= 1/2m
and
= 0
Putting the values in equation (a)
0 + mgh = 1/2m
+ 0
mgh = 1/2m
<em>cutting 'm' from both sides</em>
<em> </em>gh = 1/2
v = 
Hence, the velocity of banana before hitting the water is
v = 
Answer:22537.92 J
Explanation:
Given
mass of karen 
Distance covered by Karen =69.6 m
acceleration due to gravity=9.8
inclination
vertically karen move

h=39.72 m
Work done by escalator on karen is equal to change in potential energy of karen


The average acceleration in 0.67 m/s^2.
The average acceleration is calculated as change in velocity/time
a=(247*5/18)/(1.7*60)
=68.61/102=0.67 m/s^2
Therefor the average acceleration of the object is 0.67 m/s^2