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Shkiper50 [21]
3 years ago
11

I WILL GIVE BRAINLY !!!! Modern atomic theory states that the atom is a diffuse cloud surrounding a small, dense nucleus. Identi

fy which particle is in the nucleus.
A) ion
B) neutron
C) electron
D) free radical
Eliminate
Chemistry
1 answer:
Kay [80]3 years ago
4 0

the answer is B because i said so ;)

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5. A sample of gas occupies 1.55 L at 27 degrees Celsius and 1.00 atm pressure. What will the volume be if the pressure is incre
Sergio039 [100]

Answer:

The volume will be 0.031 L

Explanation:

Since temperature is constant, Boyle's law is applied in this case.

Boyle's law States that at constant temperature, the volume of a given mass of a gas is inversely proportional to it's pressure.

From this statement it was deduced that P1V1 = P2V2

From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.

V2 = P1V1/P2

= 1×1.55÷50

=0.031 L

5 0
3 years ago
You find a ring with a mass of 107g . You fill a graduated cylinder up with 10ml of water and put the ring into the cylinder . T
Korvikt [17]

Answer:

5 mL

Explanation:

Given data:

mass of ring = 107 g

volume of water = 10 mL

increase in volume = 15 mL

How much water displace = ?

Solution:

V (ring) = V (water + ring) - V (water)

V (ring) = 15 mL -  10 mL

V (ring) = 5 mL

when the ring is put into cylinder, volume is increased by 15 mL. The volume of water was 10 mL so water is displaced by 5 mL and the volume 5mL is the voulme of ring.

3 0
3 years ago
Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f
Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide (CO_{2})=(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}

Percentage by mass of carbon = \frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%

Percentage by mass of oxygen = \frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO_{2}

7 0
3 years ago
Read 2 more answers
What is the concentration, in m/v percent, of a solution prepared from 50 g NaCl and 2.5 L of solution?
Serjik [45]
When we convert the given mass in grams and volume in liters to m/v percent, we recall that m/v percent is expressed as grams/100 milliliters. In this case the expression becomes (50 grams/ 2500 L)*(0.1L/100ml), that is equal to 0.002 grams/ 100 mL. Hence the the concentration is equal to 0.2 m/v percent.
4 0
3 years ago
Who discovered the electron and what instrument did he use?
Leni [432]

Answer:J.J. Thomson, he was using a high-vacuum cathode-ray tube

Explanation:(I Googled it)

8 0
3 years ago
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