The reaction will produce solid copper and aluminium chloride salt.
Explanation:
Copper chloride (CuCl₂) in solution will react with aluminium to form solid cooper and aluminium chloride (AlCl₃).
3 CuCl₂ (aq) + 2 Al (s) → 3 Cu (s) + 2 AlCl₃ (aq)
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numerical problems with copper chloride and aluminium
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Answer:
Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.
Explanation:
Answer:
25 gram left
Explanation:
Given data:
Total mass = 100 g
Half life of radioactive material = 10 years
Mass left after 20 years = ?
Solution:
First of all we will calculate the number of half lives passed during 20 years.
Number of half lives = time elapsed / half life
Number of half lives = 20 years / 10 years
Number of half lives = 2
At time zero 100 g present.
At first half life = 100 g/2 = 50 g
At 2nd half life = 50 g/2 = 25 g
Thus, after 20 years 25 gram of radioactive material left.
