Answer:
6 x 10⁶ g Fe
Explanation:
Step 1: Set up dimensional analysis
7 x 10²⁸ atoms Fe (1 mol Fe/6.02 x 10²³ atoms Fe)(55.85 g Fe/1 mol Fe)
Step 2: Multiply, divide, and cancel out units
atoms Fe and atoms Fe cancel out.
mol Fe and mol Fe cancel out.
We should be left with g Fe.
7 x 10²⁸/6.02 x 10²³ = 116279 mol Fe
116279(55.85) = 6.49 x 10⁶ g Fe
Step 3: Sig figs
There is only 1 sig fig in this problem.
6.49 x 10⁶ g Fe ≈ 6 x 10⁶ g Fe
Answer:
use chemical equation to that answer
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Hope this Helps! :)
We are given the compounds:
0.2 mol pb(ch3coo)2, 0.1 mol na2s, and 0.1 mol cacl2
Pb will react with both S and Cl to form a solid compound,
therefore:
Pb+2 + S-2 ---> PbS(s) <span>
Pb+2 + 2Cl- ---> PbCl2(s) </span><span>
<span>Lead(II) sulfide and Lead(II) chloride will precipitate.</span></span>
