The answer is glyceride, hope I helped
Basically they are asking you to find the element that is most closely associated with these clues.
1. Fireworkium: 15 protons and 15 electrons? No problem. We can see that the atomic number is 15, in which in real life, the element is Phosphorous. (Phosphorous is a common element in fireworks for an explosive personality and colors)
2. Toothium: A nonmetal with average mass number close to 19? We check the periodic table once more and find that Fluorine is our answer. (Notice that fluorine is in toothpaste, which is why they decided the name Toothier)
3. Breathium: Now honestly, I didn't even have to check the periodic table but just realize that we breath Oxygen. But if you want the straight answer, Oxygen is a nonmetal which has an atomic mass close to 16, and surprise, it has one less proton than Fluorine.
4.Lightium: Immediately we see that since this gas does not react with other elements, it is a noble gas. If it glows in a lamp or vacuum tube, we can also see it is of a light origin. If it has one more proton than Toothium (Fluorine) than we can immediately see that in the periodic table, our answer is Neon.
5. Rottoneggium: We can immediately guess sulfur. The straight way shows that it has 16 electrons, and the non-ion atom should also have 16 protons. Therefore, our answer is Sulfur.
6. I just realized I forgot Floatium: If it has 2 protons, we look in the periodic table and see that our answer is Helium.
Answer:
6.25 ×10^10 Hz
Explanation:
If the distance between five successive crests is 2.4 cm, then the distance between each crest is 2.4/5 = 0.48 cm or 0.0048 m or 4.8 ×10^-3 m
Since the velocity of a wave is given by;
v= λf
Where;
λ= wavelength of the wave
f= frequency of the wave
But λ= distance between successive crests = 4.8 ×10^-3 m
v= 3×10^8 ms-1 (speed of electromagnetic waves in vacuum)
f= v/λ
f= 3×10^8 ms-1/4.8 ×10^-3 m
f= 0.625 ×10^11 Hz
f= 6.25 ×10^10 Hz
Answer:
The mass defect of a deuterium nucleus is 0.001848 amu.
Explanation:
The deuterium is:
The mass defect can be calculated by using the following equation:
![\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}](https://tex.z-dn.net/?f=%5CDelta%20m%20%3D%20%5BZm_%7Bp%7D%20%2B%20%28A%20-%20Z%29m_%7Bn%7D%5D%20-%20m_%7Ba%7D)
Where:
Z: is the number of protons = 1
A: is the mass number = 2
: is the proton's mass = 1.00728 amu
: is the neutron's mass = 1.00867 amu
: is the mass of deuterium = 2.01410178 amu
Then, the mass defect is:
![\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu](https://tex.z-dn.net/?f=%5CDelta%20m%20%3D%20%5B1.00728%20amu%20%2B%20%282-%201%291.00867%20amu%5D%20-%202.01410178%20amu%20%3D%200.001848%20amu)
Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.
I hope it helps you!
