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lana [24]
3 years ago
9

Using the method of initial rates for the reaction a → b, if the initial concentration of a is doubled and the rate of reaction

quadruples, what is the order of reaction with respect to a?
Chemistry
1 answer:
zmey [24]3 years ago
4 0
Answer is: reaction is second order with respect to a.
This second order reaction<span> is proportional to the square of the concentration of reactant a.
</span>rate of reaction = k[a]².
k is second order rate constant and have unit M⁻¹·s⁻¹.
Integrated rate law for this reaction: <span><span>1/[a]</span>=<span>1/<span>[a]</span></span></span>₀ <span>+ kt.
t is time in seconds..</span>
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omplete the relationship between ph and pka for each of the following atomic view pictures of a buffered solution.
Yakvenalex [24]

The relationship between pH and pKa of buffer solution in given atomic view:

In figure I  pH= pKa  ( since [HA] =[A-] )

In figure II pH > pKa ( since [A-] > [HA] )

In figure III pH < pKa ( since [A-] < [HA] )

The pH and pKa are related by the Henderson-Hasselbalch equation. It should not be used for concentrated solutions, extremely low pH acids, or extremely high pH bases because it is simply an approximation.

pH =  pKa + log(conjugate base/weak acid).

pH equals pKa plus log ([A-] / [HA]).

pH is determined by dividing the weak acid concentration by the log of the conjugate base concentration and the pKa value.

About halfway to the equivalence point:

pH = pKa

It's important to note that this equation is familiar with the connection because it is sometimes written for the Ka value rather than the pKa value.

pKa = – log Ka

Hence, value of pH depend on relative concentration of [A-]  and HA]

To know more about Ka.

brainly.com/question/16035742

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5 0
1 year ago
16.0 grams of molecular oxygen gas is equal to
IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

To get the number of molecules present in 16 grams of O2, we will use the formula:

         No. of molecules = no. of moles x Avogadro's number (NA)-----  eq 1)

As we know:

                        The number of moles = mass/ molar mass of molecule

Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

Putting the values in above formula:

                                                    = 16/32  

                                                     = 0.5 moles

Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

                                No. of molecules = 0.5  x 6.02 * 10^23

                                   =3.01 x 10^23 molecules

or                 301,000,000,000,000,000,000,000 molecules

This means that 16 grams of 3.01 x 10^23 molecules of oxygen.

Hope it helps!

4 0
3 years ago
Read 2 more answers
What is a serial dilution?
lord [1]

A serial dilution is the stepwise dilution of a substance in solution. Usually the dilution factor at each step is constant, resulting in a geometric progression of the concentration in a logarithmic fashion.

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3 years ago
Carnegie Development stages
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Answer:

Stage 1: 1 days.

Stage 2: 2-3 days.

Stage 3: 4-5 days.

Stage 4: 6 days.

Stage 5 (a-c): 7-12 days.

Stage 6: c. 17 days.

Stage 7: c. 19 days.

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Which of the following is a prokaryote that contains a cell wall, cell<br> membrane, and flagellum?
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Answer:

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Explanation:

hope this helps please gimme brainliest

6 0
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