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3 years ago

What’s the value of x and y?

Mathematics

1 answer:

umka21 [38]3 years ago

6 0

Answer:

x = 31

y = 18

Step-by-step explanation:

It would take a long time to explain

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What is (x-4)(2x-3)=0?

amm1812

Hi,
The answer is 3/2 or 4
How I got my answer:
Just think that (2x+3) OR (x-4) has to be 0.
<span> Than you can find it out with a simple +/- calculation. </span>
<span> 2x+3=0 x-4=0
x=-3/2 or 4</span>Hope this helps you.

7 0

3 years ago

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

3 0

3 years ago

How many sets of four consecutive positive integers are there such that the product of the four integers is less than $100,\!000

SVEN [57.7K]

Answer:

16,17,18,19

Step-by-step explanation:

one guy guessed. probably using a calculator

another guy took the 4th root of 100,000 and rounded down a number

(a third way started like this

n*(n+1)*(n+2)(n+3)=100000

4 0

2 years ago

Three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 33957. Find the largest number

lina2011 [118]

We take each number as x = 2x 3x 4x
(2x)³+(3x)³+(4x)³=33957
8x³+27x³+64x³=33957
99x³=33957
x³=33957÷99
=∛343
x=7
2x=2×7=14
3x=3×7=21
4x=4×7=28
=the three numbers are 14,21,28

4 0

3 years ago

If I equals PRT which equation is equivalent to T

snow_lady [41]

I = P · R · T
Divide both sides by P·R
I/(P·R) = T

Answer: $\frac{I}{PR} = T$

7 0

3 years ago