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natali 33 [55]
3 years ago
6

A cylindrical test specimen with a 15-mm diameter is tested axially in tension. A 0.58 mm elongation is recorded in a length of

200 mm when the load on the specimen is 36 kN. The material behaves elastically during testing. What material could the specimen be made of?a. Aluminumb. Magnesiumc. Polystyrened. Steel
Physics
1 answer:
Irina-Kira [14]3 years ago
6 0

Answer:

a. Aluminium

Explanation:

The strain of the specimen when tested

\epsilon = \frac{\Delta L}{L} = \frac{0.58}{200} = 0.0029

The area of the 15mm (0.015m) diameter specimen

A = \pi(d/2)^2 = \pi(0.015/2)^2 = 0.000177 m^2

So the stress when subjected to F = 36kN (36000 N) load is

\sigma = F/A = 36000 / 0.000177 = 203718327.2Pa

We can calculate the Young Modulus of the specimen

E = \sigma/\epsilon = 203718327.2/ 0.0029 = 70247699020 Pa = 70.25 GPa

This is Young Modulus of an Aluminium material

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aalyn [17]

Answer:

Explanation:

Let v be the velocity acquired by electron in electric field

V q = 1/2 m v²

V is potential difference applied on charge q , m is mass of charge , v is velocity acquired

2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²

v² = 844 x 10¹²

v = 29.05 x 10⁶ m /s

Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .

Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron

= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶

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3 years ago
How many atoms are in 3MgCl2?
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Answer:

3MgCl2 has 9 atoms.

Explanation:

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Their fore 6 + 3 is 9 of course. 3MgCl2 has 9 atoms.

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Please help!
Trava [24]

Answer:

3 N to the right

Explanation:

There are two forces acting on the car:

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- A force of 7 N towards the left

Therefore, the net force is given by the difference between the two, since they are in opposite directions:

F=10 N-7 N=3 N

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3 years ago
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You drop a pencil from your desk, which is 1 meter above the floor. How long does it take for the pencil to hit the floor? How f
vova2212 [387]

Answer:

1. 0.45 s.

2. 4.41 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) = 1 m

Time (t) =?

Velocity (v) =?

1. Determination of the time taken for the pencil to hit the floor.

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.8

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s.

Thus, it will take 0.45 s for the pencil to hit the floor.

2. Determination of the velocity with which the pencil hit the floor.

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 0.45 s.

Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 0.45)

v = 0 + 4.41

v = 4.41 m/s

Thus, the pencil hit the floor with a velocity of 4.41 m/s

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