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2 years ago

Mechanism of aspirin by salicyclic acid reacts with acetic acid ? Mechanism of benzoic acid from benzamide?

Chemistry

1 answer:

nexus9112 [7]2 years ago

3 0

Answer:

See explanation

Explanation:

The synthesis of aspirin is shown in the reaction scheme attached to this answer. The production of aspirin involves the reaction of acetyl salicyclic acid and acetic anhydride. HA in the reaction mechanism refers to an acid that is used in the reaction

Similarly benzamide, is converted to the carbonyl carbocation by reaction with acid. The -NH2 group is protonated and subsequently departs as a leaving group. An OH^- completes the mechanism forming a carboxylic acid. The movement of electrons is shown in the image attached.

Again, the diazotization of benzamide using sodium nitrate and concentrated HCl yields benzene diazonium chloride. Addition of water to benzene diazonium chloride yields the benzoic acid and nitrogen gas.

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A tank contains 200 gallons of water in which 300 grams of salt is dissolved. A brine solution containing 0.4 kilograms of salt

Nadusha1986 [10]

Answer:

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

Explanation:

given amount of salt at time t is A(t)

initial amount of salt =300 gm =0.3kg

=>A(0)=0.3

rate of salt inflow =5*0.4= 2 kg/min

rate of salt out flow =5*A/(200)=A/40

rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow

$dA/dt=2-(A/40)\\\\dA=2dt-(A/40)dt\\\\dA+(A/40)dt=2dt$

integrating factor

$=e^{\int\limits (1/40) \, dt}$

integrating factor $=e^{(1/40)t}$

multiply on both sides by $=e^{(1/40)t}$

$dAe^{(1/40)t}+(A/40)e^{(1/40)t} dt =2e^{(1/40)t}t\\\\(Ae^{(1/40)t})=2e^{(1/40)t}t$

integrate on both sides

$\int\limits(Ae^{(1/40)t})=\int\limits2e^{(1/40)t}dt\\\\(Ae^{(1/40)t})=2*40e^{(1/40)t}+C\\\\A=80+(C/e^{(1/40)t})\\\\A(0)=0.3\\\\0.3=80+(C/e^{(1/40)t}^*^0)\\\\0.3=80+(C/1)\\\\C=0.3-80\\\\C=-79.7\\\\A(t)=80-(79.7/e^{(1/40)t})$

after long period of time means t - > ∞

${t \to \infty}\\\\ \lim_{t \to \infty} A_t \\\\ \lim_{t \to \infty} (80)-(79/{e^{(1/40)t}}\\\\=80-(0)\\\\=80$

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

6 0

2 years ago

PLEASE ANSWER NEED BY MIDNIGHT TONIGHT!!!!!!

maksim [4K]

The equation for carbon-14 emission by Radium-223 nuclei is given below:

$^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C$

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of a substance with emission of radiation.

The equation for carbon-14 emission by Radium-223 nuclei is given below:

$^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C$

In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.

Learn more about radioactivity at: brainly.com/question/3603596

#SPJ1

5 0

1 year ago

Draw the major product for the reaction of 1-butyne with water in the presence of catalytic TfOH (i.e., CF3SO3H). Then answer th

Mademuasel [1]

Answer:

2-Butanone

Explanation:

From the given information:

The presence of mercury as an acid catalyst brings about the addition of water to the triple bond which yields enol. Then, according to Markownikov's rule and after tautomerism has occurred, we have a methyl ketone ( 2- Butanone) as the product.

The answer regarding the transformation is addition and hydration.