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Verdich [7]
3 years ago
9

Question 25 An aqueous solution at has a concentration of . Calculate the concentration. Be sure your answer has the correct num

ber of significant digits.
Chemistry
1 answer:
Natalka [10]3 years ago
8 0

The given question is lacking some details, the complete question is following

Question:

An aqueous solution at 25 °C has a OH⁻ concentration of 2.5 x 10⁻⁴ M . Calculate the H₃O⁺ concentration. Be sure your answer has the correct number of significant digits

Answer:

Concentration of H₃O⁺ is:

[H_{3}O^{+}]=4.0X10^{-9} M

Explanation:

In aqueous solutions the product of the concentration of hydronium ions H₃O⁺ and hydroxide ions OH⁻ is 1.0 x 10⁻¹⁴. This value is the dissociation or ionization constant of water at 25 °C. Its formula is given as:

Kw = [H_{3} O^{+}][OH^{-} ]

1.0 X 10^{-14}= [H_{3}O^{+}](2.5 X 10^{-4})

[H_{3}O^{+}]= \frac{1.0X10^{-14}}{2.5 X 10^{-4}}

[H_{3}O^{+}]=4.0X10^{-9} M

P.S: As the smallest number of significant figure in the ratio was two, so the answer contains two significant figures.

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Given:

Diprotic weak acid H2A:
 
Ka1 = 3.2 x 10^-6
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Balanced chemical equation:

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------------------------------
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ka1 = 3.2 x 10^-6 = [2x]^2 * [x] / (0.065 - x)

solve for x and determine the concentration at equilibrium. 


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This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det
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Answer:

0.054 mol O

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>

<em />

Step 1: Given data

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Step 2: Establish the appropriate molar ratio

According to the chemical formula, the molar ratio of C to O is 2:2.

Step 3: Calculate the moles of oxygen in the sample

We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.

0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O

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