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sergeinik [125]
2 years ago
12

28 girls and 38 boys volunteer to plant trees at a school. their teacher wants to put them in groups that have girls AND boys. h

ow many groups can the teacher make
pleaseeeeeeeeeeeeeeeeeeeeeeee solve i have a headache and cant focus so please help me out also please do step by step
Mathematics
1 answer:
Delvig [45]2 years ago
5 0

Answer:

so 14 can go into 28, 2 times and 19 can go into 38 2 times so the techaer can make 2 group with 14 girls and 19 boys in each group.

Step-by-step explanation:

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Working together, Jacob and Kristin can
Wewaii [24]

Answer:

  15 minutes

Step-by-step explanation:

Their rate together is 1/6 floor per minute.

Her rate alone is 1/10 floor per minute.

His rate is the difference of these:

  1/6 - 1/10 = 5/30 -3/30 = 2/30 = 1/15 . . . . floor per minute

It would take Jacob 15 minutes to do it alone.

6 0
3 years ago
75 students decreased by 80%
Degger [83]
Hello,

The initial amount of students is 75. The amount decreased by 80%.

new total = 75-80%

= 15

Thus, 15 students are left.

Faith xoxo
3 0
3 years ago
the sum of two numbers is 18. twice the first number increased by three times the second number equals 40. find the numbers
ryzh [129]

Answer:

4 and 14

Step-by-step explanation:

:the sum of two numbers is 18" can be written as

 x + y = 18               let x represent the first number, and y the second

"twice the first number increased by three times the second number equals 40" can be written as

2x + 3y = 40

Now solve this system. Using elimination will probably be the easier method...

1.   x +  y = 18

2.  2x + 3y = 40

Multiply equation 1 by -2 so the x variable will be the opposite of the x variable on equation 2.

1.  -2x - 2y = -36

2.  2x  + 3y = 40

Now add the equations together, cancelling out 'x'

y  = 4     ( 2x + (-2x) = 0, so 'x' is gone, 3y + (-2y) = y, 40 + (-36) = 4)

Since y = 4, plug that into either equation 1 or 2 and solve for x

1.  x + 4 = 18     (y becomes 4)

     x = 14        (subtract 4 on both sides to isolate 'x')

7 0
3 years ago
(MC 02.03) If parallelogram ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A
Soloha48 [4]

A' would lie on point A (-4 , 1)

Step-by-step explanation:

Let us revise some transformations

1. If point (x , y) reflected across the x-axis , then its image is (x , -y)

2. If point (x , y) reflected across the y-axis , then its image is (-x , y)

3. If point (x , y) rotated about the origin by angle 180°, then its image

    is (-x , -y)

Parallelogram ABCD was reflected over the y-axis, reflected over the

x-axis, and rotated 180°

We need to know where would point A' lie

∵ The coordinates of point A are (-4 , 1)

∵ The parallelogram is reflected over x-axis

∴ The sign of y-coordinate of point A changed to opposite

∴ The image of point A is (-4 , -1)

∵ The parallelogram then reflected over the y-axis

∴ The sign of x-coordinate of point (-4 , -1) changed to opposite

∴ The image of point (-4 , -1) is (4 , -1)

∵ The parallelogram then rotated 180°

∴ The signs of the x-coordinate and the y-coordinate of point (4 , -1)

   changed to opposite

∴ The image (4 , -1) is (-4 , 1)

∴ A' is (-4 , 1)

∵ Point A is (-4 , 1)

∴ A' would lie on point A

A' would lie on point A (-4 , 1)

Learn more:

You can learn more about rotation in brainly.com/question/9720317

#LearnwithBrainly

3 0
3 years ago
PLZ HELP ASAP LAST ONE ANGLE BISECTOR THEOREM
In-s [12.5K]
We have from the angle bisector theorem that the sides AC and CD are proportional to AB and BD. Hence, we get the following equality that holds in general when the angles BAD and CAD are equal.
\frac{CD}{AC} = \frac{BD}{AB}
Substituting:

\frac{2}{5.9} = \frac{2.8}{x} \\  x= \frac{5.9*2.8}{2}=8.26=8.3
6 0
2 years ago
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