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3 years ago

Please solve this for points please dont just write random stuff 40 points! and brainliest

Chemistry

1 answer:

Zepler [3.9K]3 years ago

5 0

there is not context random people cant solve this because there is no way to know what the chart means and also don't fake 40 points. I'm sorry but if you can add context I might be able to help :/

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How many grams are in 4.8 moles of Sulfur?

Ainat [17]

153.888 grams are in 4.8 moles of sulfur

5 0

4 years ago

If any atom loses 1 electron it has a charge of

uranmaximum [27]

Answer:

1 + net charge

Explanation:
The resulting ion will have
1 electron fewer surrounding the nucleus than the number of protons located inside the nucleus it will have a 1+ charge.

3 0

3 years ago

Be sure to answer all parts. ΔH o f of hydrogen chloride [HCl(g)] is −92.3 kJ/mol. Given the following data, determine the ident

Akimi4 [234]

Answer:

NH₄Cl(s) → NH₃(g) + HCl(g)

ΔH°rxn 74,89 kJ/mol

Explanation:

The change in enthalpy of formation (ΔHf) is defined as the change in enthalpy in the formation of a substance from its constituent elements. For HCl(g):

(1) ¹/₂H₂(g) + ¹/₂ Cl₂ → HCl(g) ΔH = -92,3 kJ/mol

It is possible to sum ΔH of different reactions to obtain ΔH of a global reaction (Hess's law).

For the reactions:

(2) N₂(g) + 4H₂(g) + Cl₂(g) → 2NH₄Cl(s) ΔH°rxn = −630.78 kJ/mol

(3) N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

The sum of -(2) + (3) gives:

-(2) 2NH₄Cl(s) → N₂(g) + 4H₂(g) + Cl₂(g) ΔH°rxn = +630.78 kJ/mol

(3) N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

-(2) + (3) 2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g)

ΔH°rxn = +630.78 kJ/mol −296.4 kJ/mol = +334,38 kJ/mol

Now, the sum of -(2) + (3) + 2×(1)

-(2) + (3) 2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g) ΔH°rxn = +334,38 kJ/mol

2×(1) H₂(g) + Cl₂(g)→ 2HCl(g) ΔH = 2×-92,3 kJ/mol

-(2) + (3) + 2×(1) 2NH₄Cl(s) → 2NH₃(g) + 2HCl(g)

ΔH°rxn = +334,38 kJ/mol + 2×-92,3 kJ/mol = 149,78 kJ/mol

The reaction of:

NH₄Cl(s) → NH₃(g) + HCl(g)

Has ΔH°rxn = 149,78kJ/mol / 2 = 74,89 kJ/mol

I hope it helps!

8 0

3 years ago

How to determine the number of valence electrons using the As and Bs system

xz_007 [3.2K]

Answer:Use the K L M N shell orbit

Explanation: Valence electrons are those electrons on the outermost shell of an atomic nucleus.

The K L M N electron shell is named by a spectroscopist called Charles G. Barkla, who discovered the A X-rays ( high energy rays) and the B X-rays ( low energy rays), he later renamed the A X-rays K X-rays which is the Energy level orbit, and the B X-rays was also renamed to be the L M N and so on.

PLEASE SEE PICTURE ATTACHED

THE PICTURE SHOWS HOW TO DETERMINE VALENCE ELECTRON USING THE As AND B's WHICH ARE THE K L M N SHELL ORBIT, USING SILICON AS AN EXAMPLE.

The maximum number of electron in the K orbit is 2

The maximum number of electron in the L M N shell is 8

Therefore the number of electron found in the outermost shell becomes the number of Valence electron in that element.

4 0

4 years ago

Baking soda needs an acid in the recipe in order to work. Which of these ingredients would react with the baking soda to make th

Ilya [14]

Explanation:

5.03" (and any subsequent words) was ignored because we limit queries to 32 words.

please mark me as brainliest

6 0

4 years ago