A projectile is launched at an angle above the

1 answer:

7 0

The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.

The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.

v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s

Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.

The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.

Combining this together we get:
(1) vx=40m/s and vy=10m/s

You might be interested in

the space shuttle used three parachutes to land in the image at the start of the project. Why did the space shuttle engineers us

iragen [17]

Answer:

Sep 9, 2008 - Image above: In the Parachute Refurbishment Facility at NASA's ... His parachute, when opened, had a canopy that resembled a huge umbrella. ... Space Center used mainly to process space shuttle parachutes, United Space ... Hillebrandt also is lead engineer for the Constellation Program's Ares 1 rocket ...

Explanation:

6 0

2 years ago

A ring is attached at the center of the underside of a trampoline. A sneaky teenager crawls under the trampoline and uses the ri

Karo-lina-s [1.5K]

Answer:

Explanation:

Given

Mass of mother $m=79\ kg$

Mother is released with a speed of $v=2.5\ m/s$

Assuming we need to find elastic Potential energy stored in Trampoline

Kinetic energy acquired by Mother comes from Elastic Potential Energy stored in the spring

I.e. Elastic Potential Energy=Kinetic Energy of mother

$\frac{1}{2}kx^2=\frac{1}{2}mv^2$

$E=\frac{1}{2}\times 79\times 2.5^2=246.875\ J$

So 246.875 J of Energy is stored in the trampoline as he pull the ring

5 0

3 years ago

12 seconds after starting from rest a frewly falling cantaloupe has a speed of

adoni [48]

Answer:

<em>The cantaloupe has a speed of 117.6 m/s</em>

Explanation:

<u>Free Fall Motion</u>

It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is $g = 9.8 m/s^2$ .