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Bumek [7]
2 years ago
11

A projectile is launched at an angle above the

Physics
1 answer:
gtnhenbr [62]2 years ago
7 0
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.

The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.

v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s

Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.

The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.

Combining this together we get:
(1) vx=40m/s and vy=10m/s

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A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 12.9 rad/s in 2.98 s.
PtichkaEL [24]

Explanation:

(a) Find the magnitude of the angular acceleration of the wheel.

  • angular acceleration = angular speed /time
  • angular acceleration = 12.9/2.98 = 4.329rad/s²

(b) Find the angle in radians through which it rotates in this time interval.

  • angular speed = 2x3.14xf
  • 12.9rad = 2 x3.14

  • rad = 6.28/12.9
  • rad = 0.487

Now we convert rad to angle

  • 1 rad = 57.296°
  • 0.487 = unknown angle
  • unknown angle =57.296 x 0.487 = 27.9°

The angle in radians = 27.9°

8 0
3 years ago
A sodium has an atomic number of 11 and the atomic mass of 23. Determine the its proton, electrons, and neutrons
ioda

The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu. Since sodium has 11 protons, the number of neutrons must be 23 – 11 = 12 neutrons.

7 0
3 years ago
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liubo4ka [24]

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1. stomach

2. arteries

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4. spinal cord

6 0
3 years ago
What condition is necessary for an object to make a good reference point?
777dan777 [17]
The object is fixed relative to the motion you are trying to describe.
8 0
3 years ago
An electron (q=-1.602×10-19C) is placed .03m away from spherical object with a net charge of -7.2 C.
vovangra [49]

Answer:

Explanation:

electric field at the location of electron

= 9 x 10⁹ x 7.2 / .03²

= 72 x 10¹² N/C

force on electron = electric field x charge on electron

= 72 x 10¹² x 1.6 x 10⁻¹⁹

= 115.2 x 10⁻⁷ N .

C )

work done = charge on electron x potential difference at two points

potential at .03 m

= 9 x 10⁹ x 7.2 / .03

= 2.16 x 10¹² V

potential at .001 m

= 9 x 10⁹ x 7.2 / .001

= 64.8 x 10¹² V

potential difference = (64.8 - 2.16 )x 10¹² V

= 62.64 x 10¹² V  .

work done = 62.64 x 10¹² x 1.6 x 10⁻¹⁹

= 100.224 x 10⁻⁷ J .

D )

There will be no change in the magnitude of force on positron except that the direction of force will be reversed . In case of electron , there will be repulsion and in case of positron , there will be attraction .

Work done in case of electron will be positive and work done in case of positron will be negative .

electric field due to charge will be same in both the cases .

8 0
3 years ago
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