All categories

2 years ago

A projectile is launched at an angle above the

1 answer:

7 0

The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.

The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.

v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s

Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.

The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.

Combining this together we get:
(1) vx=40m/s and vy=10m/s

You might be interested in

Mass is the amount of _____

solong [7]

<h2>Hey there! </h2>

<h3>The correct option is:</h3>

<h2>'B' material </h2>

5 0

3 years ago

Read 2 more answers

Two small insulating spheres with radius 3.50×10^−2m are separated by a large center-to-center distance of

Liula [17]

Answer:

Part (i) the magnitude E of the electric field midway between the spheres is 8.71 × 10⁵ N/C

Part (ii) the direction of the electric field is towards the negative charge

Explanation:

Given;

+q = 3.93.90μC, r = 3.50×10⁻²m

-q = −2.40μC, r = 3.50×10⁻²m

magnitude of the electric field is experienced, midway between the spheres at a distance r, r = ¹/₂ × 0.51 = 0.255 m

Electric field due to point charge is given as;

$E = \frac{F}{q} = \frac{Kq^2}{qr^2} = \frac{kq}{r^2}$

K is coulomb's constant = 8.99 x 10⁹ Nm²/C²

The positive charge on positive x-axis and the negative charge is on negative x-axis.

part (a)

The electric field due to positive charge; +q = 3.93.90μC

$E_+ = \frac{kq}{r^2}\\\\E_+ = \frac{8.99 X10^9*3.9X0^{-6}}{0.255^2}\\\\E_+= 5.3919 X10^5\frac{N}{C}$

The electric field due to negative charge; -q = −2.40μC

$E_- = \frac{kq}{r^2}\\\\E_- = \frac{8.99 X10^9*2.4X0^{-6}}{0.255^2}\\\\E_-= 3.3181 X10^5\frac{N}{C}$

From superimposition theorem

The magnitude of the electric field is;

E = E₊ + E₋

E = (5.3919 × 10⁵ + 3.3181 × 10⁵) N/C

E = 8.71 × 10⁵ N/C

Therefore, the magnitude E of the electric field midway between the spheres is 8.71 × 10⁵ N/C

Part (b)

The direction of the electric field is towards the negative charge.

7 0

3 years ago

What causes the sodium channels to open successively?

11111nata11111 [884]

<span>When Sodium moves into the neuron it causes a charge change in the neuron, making it very positive. It repolarizes by pumping sodium back out of the neuron, re-establishing the potential. Neurotransmitters transmit an impulse from one neuron to another chemically. Inhibitory neurotransmitters stop impulses, excitatory neurotransmitters create and encourage impulses. For an action potential to fire the threshold of the input source must be reached.</span>

4 0

3 years ago

With what initial velocity must an object be thrown upward from a height of 2 meters to reach a maximum hieght of 200 meters

larisa86 [58]

The equations of motion to use for a constant acceleration a = g = -9.81:
$v = gt + v_0$
$y = \frac{1}{2} g t^{2} + v_0t + y_0$

at the highest point the velocity must be zero:
$0 = gt + v_0 \\ v_0 = -gt$
combine both equations:
$y = \frac{1}{2} \frac{v_0^{2} }{g} - \frac{v_0^{2} }{g} + y_0= -\frac{1}{2} \frac{v_0^{2} }{g} + y_0$
Solve for v₀:
$v_0 = \sqrt{2g(y_0 - y)}$

6 0

3 years ago

A fox runs for 12 seconds at a speed of 9.65 m/s. How much distance does it cover? Exact answer, do NOT round.

Stella [2.4K]

Answer:

115.8

Explanation:

7 0

3 years ago