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3 years ago

HELP PLEASE!!!!! pulleys, wheels, and axels.

Physics

2 answers:

Sergeu [11.5K]3 years ago

8 0

Your answer is C. 500 N

Hope this helps!!

babymother [125]3 years ago

6 0

The answer is C . 500 N

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The nuclear equation is incomplete.<br><br><br>What particle completes the equation?

Romashka-Z-Leto [24]

Answer:

$_{6}^{12} C$

Explanation:

$_{1}^{1}H+_{7}^{15}N ---> _{6}^{12} C+ _{2}^{4}He$

1+7 = 6+2 =8 -protons

1+15 = 12+4 = 16 - protons +neutrons

3 0

3 years ago

A balloon is ascending at 12.4m/s at a height of 81.3m above the ground when a package is dropped. a) How long did it take to re

tankabanditka [31]

Answer:

3secs

Explanation:

Given the following parameters

height H= 81.3m

Velocity v = 12.4m/s

Required

Time it take to reach the ground

Using the equation of motion

H = ut+1/2gt²

81.3 = 12.4t + 1/2(9.8)t²

81.3 = 12.4t + 4.9t²

4.9t² + 12.4t - 81.3 = 0

Using the general formula to find t

t = -12.4±√12.4²-4(4.9)(-81.3)/2(4.9)

t = -12.4±√153.76+1593.48/2(4.9)

t = -12.4±√1747.24/9.8

t = -12.4+41.8/9.8

t = 29.4/9.8

t = 3secs

Hence it took 3secs to reach the ground

5 0

3 years ago

A dad takes his kids to their school just 8.0 miles down the road but with traffic it takes him 30 minutes and the fastest he ca

VARVARA [1.3K]

Answer:C 24 mi/hr

Explanation:

8 0

3 years ago

Please need help on this one

jolli1 [7]

Answer:

The second answer from the top, no the energy in the wave pushed the water particles from above the earthquake in the opposite direction.

Explanation:

I believe this is the correct answer. Hope you do well

4 0

2 years ago

Read 2 more answers

What is the strength of the electric field 0.1 mmmm below the center of the bottom surface of the plate

Aleksandr [31]

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The values is $E =248.2 \ N/C$

Explanation:

From the question we are told that

The diameter is $d = 12 \ cm = 0.12 \ m$

The charge is $Q = 4.4 nC = 4.4 *10^{-9} \ C$

The distance from the center is $k = 0.1 \ mm = 1*10^{-4} \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2}$

=> $r = \frac{0.12}{2}$

=> $r = 0.06 \ m$

Generally electric field is mathematically represented as

$E = \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 + k^2 } } ]$

substituting values

$E = \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 + (1.0*10^{-4})^2 } } ]$

$E =248.2 \ N/C$

4 0

3 years ago