What is the velocity of an object that has been in free fall for 2.5s?

Physics

1 answer:

yan [13]3 years ago

3 0

<h2 /><h2>✏️ Development:</h2><h2 />

✍ We can this formula:

$\huge {\boxed {\sf v = g \cdot t }}$

Looking like this:

$\huge {\text {$ \sf v = 9,8 \cdot 2,5 \Longrightarrow \boxed {\boxed {\bf v= 24,5 }} $ }}$

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Explanation:

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If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________

siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be $V_e = \sqrt{\dfrac{GM}{r}}$ .

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

$V_e=\sqrt{\dfrac{2GM}{r}}$

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

$V_e=\sqrt{\dfrac{2GM}{r\times 2}}$

$V_e = \sqrt{\dfrac{GM}{r}}$ .

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be $V_e = \sqrt{\dfrac{GM}{r}}$ .

To know more about escape velocity follow

brainly.com/question/14042253

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1 year ago

True or false question please help me out

Len [333]

Answer:

thats true

Explanation:

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2 years ago