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Tpy6a [65]
3 years ago
15

What is the velocity of an object that has been in free fall for 2.5s?

Physics
1 answer:
yan [13]3 years ago
3 0
<h2 /><h2>✏️ Development:</h2><h2 />

✍ We can this formula:

\huge {\boxed {\sf v = g \cdot t }}

  • Looking like this:

\huge {\text {$ \sf v = 9,8 \cdot 2,5 \Longrightarrow \boxed {\boxed {\bf  v= 24,5 }} $ }}

<h3>/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/</h3>

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The total resistance of a parallel circuit is 25 ohms. If the total current is 100mA, how much current is through a 220 ohm resi
gulaghasi [49]

Answer:

The current across the resistance is 0.011 A.

Explanation:

Total resistance, R = 25 ohms

Total current, I = 100 mA = 0.1 A

Let the voltage is V.

By the Ohm's law

V = I R

V = 0.1 x 25 = 2.5 V

Now the resistance is R' = 220 ohm

As they are in parallel so the voltage is same. Let the current is I'.

V = I' x R'

2.5 = I' x 220

I' = 0.011 A

7 0
3 years ago
A simple pendulum bhas a period of 3.45s when the length of the pendulum is shortened by 1m the period is 2.81s caculate the ori
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7 0
3 years ago
An airplane flies with a velocity of 55.0 m/s [ 35° N of W] with respect to the air (this is
rodikova [14]

Answer:

21 m/s.  

Explanation:

The computation of the wind velocity is shown below:

But before that, we need to find out the angles between the vectors

53° - 35° = 18°

Now we have to sqaure it i.e given below

v^2 = 55^2 + 40^2 - 2 · 55 · 40 · cos 18°

v^2 = 3025 + 1600 - 2 · 55 · 40 · 0.951

v^2 = 440.6

v = √440.6

v = 20.99

≈ 21 m/s

Hence, The wind velocity is 21 m/s.  

6 0
3 years ago
A 26.2-kg dog is running northward at 3.02 m/s, while a 5.30-kg cat is running eastward at 2.74 m/s. Their 65.1-kg owner has the
REY [17]

Answer:

Angle with the +x axis is θ = 79.599degree

Then the velocity of owner = 1.235m/s

Explanation:

Given that the mass of dog is m1 =26.2 kg

velocity of dog is u1 = 3.02 m/s (north)

mass of cat is m2 = 5.3 kg

velocity is u2 = 2.74 m/s (east )

Mass of owner is M = 65.1 kg

Consider the east direction along +x axis andnorth along +y

momentum of dog is Py = m1 x u1

= 79.124 kg.m/s (j)

momentum of cat is Px = m2 x u2

= 14.522 kg.m/s (i)

Then the net magnitude of momentum is P = (Px2 + Py2)1/2

= 80.445

Angle with the +x axis is θ =tan-1(Py / Px ) = 79.599 degree

Then the velocity of owner is v = P / M = 1.235 m/s

3 0
3 years ago
is the rate at which ____________________ changes. (Velocity or Acceleration, velocity or acceleration)
Troyanec [42]

<u>Acceleration</u> is the rate at which <u>velocity</u> changes.

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3 years ago
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