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Tpy6a [65]
3 years ago
15

What is the velocity of an object that has been in free fall for 2.5s?

Physics
1 answer:
yan [13]3 years ago
3 0
<h2 /><h2>✏️ Development:</h2><h2 />

✍ We can this formula:

\huge {\boxed {\sf v = g \cdot t }}

  • Looking like this:

\huge {\text {$ \sf v = 9,8 \cdot 2,5 \Longrightarrow \boxed {\boxed {\bf  v= 24,5 }} $ }}

<h3>/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/</h3>

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Suppose the tip of the minute hand of a clock is two inches from the center of the clock. Determine the distance traveled by the
sashaice [31]
1) The minute travels the circumference of a 4 inches circle is 60 minutes:

Circumference = 2πr = 2π(2in) = 4π in
Time = 60 minutes

2) Constant angular velocity => (4π / 60) = (x / 20) => x = 4π / 3 inches

x = 4.19 inches

Answer: 4.19 inches

4 0
3 years ago
Write one general properties of non contact force​
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Answer:    Gravitational force between the two masses does not depend on the medium separating two masses.

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3 years ago
A transmission diffraction grating with 420 lines/mm is used to study the light intensity of di event orders (n). A screen is lo
Goshia [24]

Answer:

Explanation:

Diffraction grating is used to form interference pattern of dark and bright band.

Distance between adjacent slits (a ) = 1 / 420 mm

= 2.38 x 10⁻³ mm

2.38 x 10⁻⁶ m

wave length of red light

= 680 x 10⁻⁹ m

For bright red band

position x on the screen

= n λD / a ,         n = 0,1,2,3 etc

D = distance of screen

putting n = 1 , 2 and 3 , we can get three locations of bright red band.

x₁ = λD / a

=  680 x 10⁻⁹ x 2.8 / 2.38 x 10⁻⁶

= .8 m

= 80 cm

Position of second bright band

= 2 λD / a

= 2 x 80

= 160 cm

Position of third bright band

= 3 λD / a

= 3 x 80

= 240 cm

5 0
3 years ago
A man ties one end of a strong rope 8.17 m long to the bumper of his truck, 0.524 m from the ground, and the other end to a vert
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Answer:

2442.5 Nm

Explanation:

Tension, T = 8.57 x 10^2 N

length of rope, l = 8.17 m

y = 0.524 m

h = 2.99 m

According to diagram

Sin θ = (2.99 - 0.524) / 8.17

Sin θ = 0.3018

θ = 17.6°

So, torque about the base of the tree is

Torque = T x Cos θ x 2.99

Torque = 8.57 x 100 x Cos 17.6° x 2.99

Torque = 2442.5 Nm

thus, the torque is 2442.5 Nm.

8 0
3 years ago
Why do scientists believe that dark matter exists even though it cannot be seen?
poizon [28]
Because although they cannot see it, they can see it's influence on objects that can be seen, and it's effects.
3 0
3 years ago
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