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kenny6666 [7]
3 years ago
5

Please help asap I need my grade up in an hour lol

Physics
1 answer:
Simora [160]3 years ago
4 0

Answer:

left = 6:19 pm ; middle = 6:56 pm ; right = 9:05 am

Explanation:

You might be interested in
Why are voltages always measured between two points??
sukhopar [10]

Answer:

We describe electrical circuits similarly: current is the rate at which charge flows past a point, while the voltage is effectively like an electrical “pressure.” Voltage is always measured between two points and indicates the force “pushing” charges to flow from one point to another.

7 0
3 years ago
A planet orbits a star along an elliptical path from point X to point Y, as shown in the figure. In which of the following syste
8090 [49]

Answer:

The correct answer is Option D, the closed system containing the planet and the star.

Explanation:

To start, we need to define mechanical energy: the energy an object has from its motion and position.

The fundamental principle in physics is that the total energy in a closed system stays constant, even if it transforms. By saying "closed system," we refer to a system isolated from its surroundings. Energy never leaves the system; it only moves from one part to another.

This statement only applies to closed systems, however. An open system that interacts with its environment works differently. Energy may enter and leave the system through interaction with external forces, and this includes mechanical energy. For this reason, Option A and Option B are incorrect.

The remaining two options, C and D, only vary with the objects in the closed system. Option D includes the star; Option C does not.

However, we should take a closer look at Option C. Can an object have potential energy with itself? No, it cannot. It only has potential energy with other bodies. If the system is defined as the planet only, the only type of energy present is kinetic energy. We know a planet orbiting a star has more kinetic energy near and more gravitational potential energy further from its star. Thus it has less kinetic energy further from its star and less mechanical energy. Because of this, Option C is incorrect.

The only answer left is Option D. If we define the planet and star as a closed system, we find no net external force acting on it. Consequently, it obeys the law of conservation of energy. From prior reasoning, we know mechanical energy includes potential energy and kinetic energy and that the amounts of these energies vary with its orbit. As a result, mechanical energy is always conserved and always the same. In the end, the correct answer is Option D.

4 0
3 years ago
Hi people; there's a question that has been so confusing for me and a friend of mine.
Alborosie

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32

In our case x = 0, then y will be:

(0^{\circ}C * \frac{9}{5})+32=32

y=32^{\circ}F

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

0^{\circ}C+0^{\circ}C=32^{\circ}F

I hope it helps you!              

7 0
3 years ago
In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6
stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

                                      r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

                                      r₂= 7.5 cm

head upto water level is to rise = 60 + 5

                                          = 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q  

 π r₁² v₁ = π r₂² v₂  = 0.015

 v_1= \dfrac{r_2^2}{r_1^2} v_2

 v_1= \dfrac{7.5^2}{5^2} v_2

 v_1= 2.25 v_2

 v_2 = \dfrac{0.015}{\pi r_2^2}

 v_2 = \dfrac{0.015}{\pi 0.075^2}

    v₂ = 0.848 m/s

    v₁ = 1.908 m/s

Applying Bernoulli's equation

 P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h

 P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65

 P_p= 635539.32 Pa

 P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

6 0
4 years ago
A car is raised on a lift at a service station (so it has some amount of gravitational potential energy relative to the ground).
kenny6666 [7]

Answer:Twice

Explanation:

It is given that car is raised on a lift with respect to ground.

Suppose car is raised by a height of h m from ground having mass m so gain in Potential Energy by car is

Gain in P.E._1=m\times g\times h

Now if it were raised twice as high,i.e. 2 h height from ground then gain in Gravitational Potential Energy

=m\times g\times 2h

P.E._2=2m\cdot g\cdot h

It is clear that P.E._2=2\cdot P.E._1

Thus in second case gain in Potential Energy is twice as compared to first case

8 0
4 years ago
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