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kenny6666 [7]
3 years ago
5

Please help asap I need my grade up in an hour lol

Physics
1 answer:
Simora [160]3 years ago
4 0

Answer:

left = 6:19 pm ; middle = 6:56 pm ; right = 9:05 am

Explanation:

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If the resistivity of copper is less than that of gold at room temperature, which of the following statements must be true? Gold
KiRa [710]

Answer:

Gold Has A Higher Resistance Than Copper. The Sample Of Gold Is Thinner Than The Sample Of Copper. Electrons In Gold Are More Likely To Be Scattered Than Electrons In Copper At Room Temperature When they are exelerated by the same electric field.

Explanation:

5 0
3 years ago
In your own words, explain what non-contact forces are.
katrin [286]
It’s a force which acts on an object without coming physically in contract with it.
4 0
3 years ago
Newton’s third law of motion explains the two forces namely ‘action’ and ‘reaction’ coming into action when the two bodies are i
SIZIF [17.4K]

(b) Always act on the different bodies in opposite directions

7 0
3 years ago
Read 2 more answers
Which equation represents mass-energy equivalence? E = m2c E = mc2 E = (mc)2 E = mc
motikmotik

Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be

E = mc^2

where

m = mass in kg

c = speed of light in m/s

this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle

So correct relation above will be

E = mc^2

4 0
4 years ago
Read 2 more answers
Firecracker A is 300 m from you. Firecracker B is 600 m from you in the same direction. You see both explode at the same time. D
ss7ja [257]

Answer:

e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Explanation:

This is an ejercise in special relativity, where the speed of light is constant.

Let's carefully analyze the approach, we see the two events at the same time.

The closest event time is

       c = (x₁-300) / t

       t = (x₁-300) / c

The time for the other event is

       t = (x₂- 600) / c

since they tell us that we see the events simultaneously, we can equalize

        (x₁ -300) / c = (x₂ -600) / c

         x₁ = x₂ - 300

We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

3 0
3 years ago
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