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3 years ago

Hi people; there's a question that has been so confusing for me and a friend of mine.

Physics

1 answer:

Alborosie3 years ago

7 0

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

$y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32$

In our case x = 0, then y will be:

$(0^{\circ}C * \frac{9}{5})+32=32$

$y=32^{\circ}F$

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

$0^{\circ}C+0^{\circ}C=32^{\circ}F$

I hope it helps you!

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Background information about reflection and refraction of light

KIM [24]

Answer:

reflection :

angle of reflection and angle of incidence is equal
Incident ray and reflect d ray plus normal lies on the same plan on a same point
light reflect uniformly if it is incident on a plan surface

refraction :

light will refrect if light goes from rare medium to a dense medium or vice versa
after the light is refracted, it retunes to its original direction
angle of incidence is not equal to the angle of refraction

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3 years ago

Why do nonmetals have a negative oxidation number

galina1969 [7]

Oxygen has a higher electro negativity that then Sulfur, so Sulfur will " lose" electrons to Oxygen and that is the electrons will be pulled closer to the Oxygen causing, for oxygen to have a negative charge and the Sulfur to have a positive charge

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4 years ago

I will mark as the brainliest answer plz 8,9,10

blagie [28]

Answer:

8. acceleration = $\dfrac{d(velocity)}{d(time)}$ = 1 unit .

9. acceleration = $\dfrac{d(velocity)}{d(time)}$ = -1 unit.

10. acceleration = $\dfrac{d(velocity)}{d(time)}$ = 0 units.

Explanation:

8. i) acceleration = velocity / time

ii) In this figure velocity = time

iii) therefore acceleration = $\dfrac{d(velocity)}{d(time)}$ = 1 unit .

9. i) acceleration = velocity / time

ii) In this figure 4 = m + 5, therefore m = -1

therefore velocity = (-0.5 $\times$ time) + 5

iii) therefore acceleration = $\dfrac{d(velocity)}{d(time)}$ = -1 units.

10.) velocity is constant at 2

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5 0

3 years ago

The 480 g bar is rotating as shown what is the angular momentum of the bar about the axle?

Greeley [361]

On a similar problem wherein instead of 480 g, a 650 gram of bar is used:

Angular momentum L = Iω, where
I = the moment of inertia about the axis of rotation, which for a long thin uniform rod rotating about its center as depicted in the diagram would be 1/12mℓ², where m is the mass of the rod and ℓ is its length. The mass of this particular rod is not given but the length of 2 meters is. The moment of inertia is therefore 
I = 1/12m*2² = 1/3m kg*m² 

The angular momentum ω = 2πf, where f is the frequency of rotation. If the angular momentum is to be in SI units, this frequency must be in revolutions per second. 120 rpm is 2 rev/s, so 
ω = 2π * 2 rev/s = 4π s^(-1) 

The angular momentum would therefore be 
L = Iω 
= 1/3m * 4π 
= 4/3πm kg*m²/s, where m is the rod's mass in kg. 

The direction of the angular momentum vector - pseudovector, actually - would be straight out of the diagram toward the viewer. 

Edit: 650 g = 0.650 kg, so 
L = 4/3π(0.650) kg*m²/s 
≈ 2.72 kg*m²/s

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3 years ago

Three blocks are shown: Three blocks are shown. Block A has mass 3 kilograms, length 6 centimeters, height 4 centimeters, and wi

Yakvenalex [24]

Answer:

Block A has the greatest density.

Explaination:

Block A density:0.0625 kg/cm3

Block B density:0.020833 kg/cm3

Block C density:0.041667 kg/cm3

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3 years ago