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QveST [7]
3 years ago
15

Hi people; there's a question that has been so confusing for me and a friend of mine.

Physics
1 answer:
Alborosie3 years ago
7 0

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32

In our case x = 0, then y will be:

(0^{\circ}C * \frac{9}{5})+32=32

y=32^{\circ}F

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

0^{\circ}C+0^{\circ}C=32^{\circ}F

I hope it helps you!              

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A block of weight mg sits on an inclined plane as shown in (Figure 1) . A force of magnitude F1 is applied to pull the block up
svlad2 [7]

Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

Y Axis  

       N - W_{y} =

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X axis

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Let's use trigonometry to find the components of the weight

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We substitute

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Work is defined by

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The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

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