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Basile [38]
3 years ago
10

A 50.0 g sample of an unknown substance, initially at 20.2 °C, was heated with 1.55 kJ of energy. The final temperature of the s

ubstance was 125.0 °C. Determine the specific heat of this substance.
Chemistry
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

0.296j/g⁰c

Explanation:

we have the following information from this question before us.

mass iv substance = 50grams

we have initial temperature ti = 20.2⁰c

final temperature = 125⁰c

the energy that was provided = 155kj

we proceed with this formula

energy = mcΔT

1.55x10³ = 50 x c x (125-20.2)

1.55x10³ = c x 50gm x 104.8k

we divide through to get c

c = 1.55x10³/50g x 104.8

c = 0.296J/g⁰c

that is the specific heat of this substance.

thank you!

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Answer:

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In the problem, the phenylmagnesium chloride is the grignard reagent. The volume of 2.0 M phenylmagnesium chloride solution you need to add 2.9 mmol is:

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<em></em>

I hope it helps!

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The equation is Mr=Mi(1/2)^n

where n is the number of half-lives

Mr is the mass remaining after n half lives

Mi is the initial mass of the sample

To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)

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So Mr=5x(1/2)^1=2.5 g

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  • The half life is the time in which the concentration of a substance decreases to half of the initial value.

Learn more about half life at:

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This problem is off the jurisdiction of natural science.

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