Formation reaction is the formation of 1 mole of product from the constituents of the reactant molecules. The mass of oxygen that must react is 182 gm.
<h3>What is mass and molar mass?</h3>
Mass of the substance is the weight while the molar mass of the substance is the addition of the atomic mass of the individual mass of the constituent atoms of the compound or the molecule.
The chemical reaction can be shown as:
From the reaction, it can be said that 3 moles of oxygen are required to produce 2 moles of aluminium oxide, so x moles of oxygen will be required to produce 3.80 moles of aluminium oxide.
Solving for x:
If 1 mol of oxygen is 32 gm then 5.7 moles of oxygen will be 182.4 gm.
Therefore, option D. 182 gm is the mass of oxygen required.
Learn more about moles and molar mass here:
brainly.com/question/893495
Answer:
A mixture is a combination of two or more pure substances that are not chemically combined. Mixtures are held together by physical forces and therefore can be separated physically.
Mass 1 + %abundance of first isotope + Mass 2 + %abundance of second isotope
/ 100
This is RAM.
Answer:
15.0 L
Explanation:
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (mmHg)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)
-----> T = temperature (K)
To calculate the volume, you need to (1) convert grams C₄H₁₀ to moles (via the molar mass), then (2) convert the temperature from Celsius to Kelvin, and then (3) calculate the volume (via the Ideal Gas Law).
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
32 grams C₄H₁₀ 1 moles
------------------------- x ----------------------- = 0.551 moles C₄H₁₀
58.124 grams
P = 728 mmHg R = 62.36 L*mmHg/mol*K
V = ? L T = 45.0 °C + 273.15 = 318.15 K
n = 0.551 moles
PV = nRT
(728 mmHg)V = (0.551 moles)(62.36 L*mmHg/mol*K)(318.15 K)
(728 mmHg)V = 10922.7632
V = 15.0 L
the correct anwser is B
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