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tekilochka [14]
2 years ago
10

The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2). 4Al 3O2 Right arro

w. 2Al2O3 The molar mass of O2 is 32. 0 g/mol. What mass, in grams, of O2 must react to form 3. 80 mol of Al2O3? 60. 8 grams 81. 1 grams 122 grams 182 grams.
Chemistry
1 answer:
Andrew [12]2 years ago
3 0

Formation reaction is the formation of 1 mole of product from the constituents of the reactant molecules. The mass of oxygen that must react is 182 gm.

<h3>What is mass and molar mass?</h3>

Mass of the substance is the weight while the molar mass of the substance is the addition of the atomic mass of the individual mass of the constituent atoms of the compound or the molecule.

The chemical reaction can be shown as:

\rm 4 Al + 3 O_{2} \rightarrow 2 Al_{2}O_{3}

From the reaction, it can be said that 3 moles of oxygen are required to produce 2 moles of aluminium oxide, so x moles of oxygen will be required to produce 3.80 moles of aluminium oxide.

Solving for x:

\begin{aligned}\rm 2x &= 3.80\times 3\\\\\rm x &= \dfrac{11.4}{2}\\\\&= 5.7\;\rm mol\end{aligned}

If 1 mol of oxygen is 32 gm then 5.7 moles of oxygen will be 182.4 gm.

Therefore, option D. 182 gm is the mass of oxygen required.

Learn more about moles and molar mass here:

brainly.com/question/893495

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When pH changes from 6 to 3, how many times does acidity increase?
photoshop1234 [79]

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8 0
3 years ago
a flask was filled with SO2 at a partial pressure of 0.409 atm and O2 at a partial pressure of 0.601 atm. The following gas-phas
jarptica [38.1K]

Answer:

The equilibrium partial pressure of O2 is 0.545 atm

Explanation:

Step 1: Data given

Partial pressure of SO2 = 0.409 atm

Partial pressure of O2 = 0.601 atm

At equilibrium, the partial pressure of SO2 was 0.297 atm.

Step 2: The balanced equation

2SO2 + O2 ⇆ 2SO3

Step 3: The initial pressure

pSO2 = 0.409 atm

pO2 = 0.601 atm

pSO3 = 0 atm

Step 4: Calculate the pressure at the equilibrium

pSO2 = 0.409 - 2X atm

pO2 = 0.601 - X atm

pSO3 = 2X

pSO2 = 0.409 - 2X atm = 0.297

 X = 0.056 atm

pO2 = 0.601 - 0.056 = 0.545 atm

pSO3 = 2*0.056 = 0.112 atm

Step 5: Calculate Kp

Kp = (pSO3)²/((pO2)*(pSO2)²)

Kp = (0.112²) / (0.545 * 0.297²)

Kp = 0.261

The equilibrium partial pressure of O2 is 0.545 atm

3 0
3 years ago
Answer the following question using the reaction: AB ---&gt; A+B
Vadim26 [7]

Answer:

So whats the question?

Explanation:

3 0
3 years ago
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