When q is the heat energy in joules (J)
so, according to this formula, we can get q (in joule unit):
q = M*C*ΔT
when M is the mass of the water sample = 1.85 g
C is the specific heat capacity of water = 4.18 J/g.°C
and Δ T is the difference in temperature (Tf-Ti) = 33 - 22 = 11°C
So, by substitution, we will get the value of q ( in Joule):
∴ q = 1.85 g * 4.18 J/g.°C * 11 °C
= 85 J
Answer:
Water: H2O --> [H+] + [OH-]
Ethyl alcohol: C2H5OH --> [C2H5O-] + [H+]
Explanation:
Dipole-dipole force is observed when an ionic compound ionizes (forms ions), revealing its slightly positive ion and slightly negatively ion.
The chemical formula of Water is H2O.
H2O --> [H+] + [OH-]
The chemical formula of ethyl alcohol is C2H5OH.
C2H5OH --> [C2H5O-] + [H+]
Note the positive and negative parts of both water and ethyl alcohol as expressed in the equations above.
Answer:
1.70 g.cm⁻³
Solution:
Data Given;
Mass = 84.7 g
Volume = 49.6 cm³
Density = ?
Formula Used;
Density = Mass ÷ Volume
Putting values,
Density = 84.7 g ÷ 49.6 cm³
Density = 1.70 g.cm⁻³
Conjugate base of Propanoic acid (
is propanoate where -COOH group gets converted to -CO
. The structure of conjugate base of Propanoic acid is shown in the diagram.
The 
above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.
= 
+ log![\frac{[Conjugate base]}{[acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BConjugate%20base%5D%7D%7B%5Bacid%5D%7D)
=4.9+log
=5.85
As 90% conjugate base is present, so propanoic acid present 10%.
Answer:
The boiling point of milk is close to the boiling point of water, which is 100 degrees C, or 212 degrees F at sea level, but milk contains additional molecules, so its boiling point is slightly higher.
Explanation:
