Q=mc(change in temp)
Q is amount of heat, m is mass, c is specific heat
Water:
Q= (50.0g)(4.18 J/g°C)(63°C)
Q= 13167J
Aluminum:
Q= (200.0g)(0.900 J/g°C)(63°C)
Q= 11340J
Water requires more heat
To solve this problem we can use following equation.
v =u + at
Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).
v = 7 m/s
u = 4 m/s
a = ?
t = 5 s
By applying the equation, we can get
7 m/s = 4 m/s + a x 5 s
3 m/s = a x 5 s
a = 0.6 m/s²
Hence, the acceleration is 0.6 m/s² towards north.
Answer is "C".
The specific heat, c is 0.75 J/g°C
<u>Explanation:</u>
Heat or Energy, Q = 1500J
Mass, m = 50g
T1 = 0°C
T2 = 40°C
Specific Heat, c = ?
We know,
Q = mcΔT
Q = mc(T2-T1)
1500 = 50 X c X (40-0)
1500 = 50 X c X 40
c = 1500/ 2000
c = 0.75 J/g°C
Therefore, the specific heat, c is 0.75 J/g°C
