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vesna_86 [32]
3 years ago
8

When do we say a curvilinear motion is accelerated?​

Physics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

There always is an acceleration in a curvilinear motion, as the velocity vector changes, so always.

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The Kelvin scale is also know as the absolute zero<br> TRUE OR FALSE
Bond [772]

The Kelvin scale is also called absolute zero scale

Explanation:

true

6 0
3 years ago
A 9,900 kg object feels a gravitational force of 12 N due to a 52,000 kg object. What is the distance between the
aleksley [76]

Answer:

0.05 m

Explanation:

From the question given above, the following data were obtained:

Mass of first object (M1) = 9900 kg

Gravitational force (F) = 12 N

Mass of second object (M2) = 52000 kg

Distance apart (r) =?

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Thus, we can obtain the distance between the two objects as shown below:

F = GM1M2/r²

12 = 6.67×10¯¹¹ × 9900 × 52000 /r²

Cross multiply

12 × r² = 6.67×10¯¹¹ × 9900 × 52000

Divide both side by 12

r² = (6.67×10¯¹¹ × 9900 × 52000)/12

Take the square root of both side

r = √[(6.67×10¯¹¹ × 9900 × 52000)/12]

r = 0.05 m

Therefore, the distance between the two objects is 0.05 m

3 0
3 years ago
It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used
stepladder [879]

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

a_{c} = rω²

ω² = a_{c} / r

ω = √( a_{c} / r )

where r is the radius of the cylinder

ω is the angular velocity

given that; the centripetal acceleration equal to the acceleration of gravity a a_{c}  = g = 9.8 m/s²

so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

7 0
3 years ago
What are the primary differences between stars and planets
shusha [124]
Stars don't have moons and planets do
6 0
3 years ago
Read 2 more answers
Sam lifted his backpack with 5 Newtons of force a total of 400
irga5000 [103]

2000joules

Explanation:

work done=force×meters

4 0
3 years ago
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