Identify the type of particle that would be given off by each of the following nuclear reactions:

Where will the strongest force be excerted by the scissor blades to cut through a piece of material? Explain your answer.

asambeis [7]

Answer:

in the thick part of the scissors ✂️

Explanation:

because in physics simple machine called wedge the force applied in this thick area it have thine side used to split or piece objects

8 0

2 years ago

Difference between constant speed and average speed

Tresset [83]

If a body is traveling with constant speed , it means that it's distance is constantly increasing with time.

If it goes 5m in 3min , it will go 5m in next 3 min.

Average velocity is the total displacement divided by total time.

When the body travels 5m in 3 min and 25 m in next 3min , average velocity
=(25+5)/(3+3)
=30/6
=5m/min

8 0

3 years ago

The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in

chubhunter [2.5K]

Answer:

The angular separation equals $0.35^{o}$

Explanation:

We have according to Snell's law

$n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})$

$\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})$

Using this equation for both the colors separately we have

$\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}$

Similarly for violet light we have

$\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}$

Thus the angular separation becomes

$\Delta \theta =14.48-14.13=0.35^{o}$

6 0

4 years ago

Select the correct answer. Which statement best explains the relationship between electric force and the charges on two interact

shtirl [24]

Answer:

Electrical force is directly proportional to the product of the charges on the two objects.

7 0

3 years ago

Read 2 more answers

A car on a straight flat road races a boat on a calm canal parallel to the road. The car has a constant acceleration of 1.95m/s2

Gelneren [198K]

Answer:

The winner of the race is the boat because the it get to the goal a time of t=42.42 seg

Explanation:

The problem has tow steps the first one is the time takes each vehicule to get the top speed.

1.

$V_{f} = V_{o} + a*t \\V_{o}= 0 \frac{m}{s} \\t = \frac{V_{f} }{a} \\t_{1} = \frac{41 \frac{m}{s} }{1.95 \frac{m}{s^{2} } }=21.02 s \\t_{2} = \frac{32 \frac{m}{s} }{6.5 \frac{m}{s^{2} } } =4.92 s$

2.

Now after they take the top speed have to know who get first to the goal

$x_{f}= x_{o} + v_{o}*t + \frac{1}{2}* a *t^{2}\\ a=0 \frac{m}{s^{2} }\\ x_{o}= 0$

So the speed Vo is now the final velocity calculated before

$t= \frac{x_{f} }{V_{o} } \\t1= \frac{1200m }{41\frac{m}{s} } = 29.2 s\\t2= \frac{1200m }{32\frac{m}{s} } = 37.5 s\\$

$t1_{total}= 21.2+29.2=50.22 s\\ t2_{total}= 4.91+37.5=42.41 s$

4 0

4 years ago