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svetoff [14.1K]
3 years ago
8

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

questions. Qualitative and Quantitative Data Explain why it is important to use both qualitative data and quantitative data.
Physics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer: It is important to use both QUALITATIVE and QUANTITATIVE data because the limitations of one type of data are counteracted by the advantages of the other.

Explanation:

QUALITATIVE data defined as type of data that centers on the measurement of the features of the subject under study. This is obtained through careful observations. It is a non numerical type of data. Some examples includes: sex(male or female), name, and colours. The limitations of using only qualitative data for a research includes:

--> it can not be statistically represented

--> the results can not be verified

--> it is time consuming and

--. It requires alot of labor.

QUANTITATIVE data is defined as the type of data that centers on the measurement of the amount and quantity of the subject under study. It can be used to conduct a large study than qualitative data. Examples include the heights and weights of students. The limitations of quantitative research includes:

--> poor representation of target population

--> inability to control the environment and

--> lack of resources for data collection.

Therefore, It is important to use both QUALITATIVE and QUANTITATIVE data analysis because the limitations of one type of data are counteracted by the advantages of the other. I hope this helps, thanks!

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Explain how energy allows a paper clip to be attracted to a magnet
ELEN [110]

I really don’t know maybe energy from the poles just attaches and the soil comes and energy lifts the matter of soil and the magnet follows and lifts and goes up to the soil and the poles attach the magnet to the soil and the energy lifts the magnet and the soil follows and it is attracted to the magnet

6 0
4 years ago
Read 2 more answers
The conventional relatively small unit for work(ignoring time) such as raising one pound one foot is the foot-pound(ft. lb.). Si
Lelechka [254]

Answer:

1 joule = 0.737 foot-pound

Joule is the unit of work.

1 J = 1 N·m

In SI units

1 J = 1 kg· m/s²

0.737 foot-pound is the amount of work to raise 0.737 pounds one foot or raising one pound to 0.737 ft.

6 0
3 years ago
A 1640 kg merry-go-round with a radius of 7.50 m accelerates from rest to a rate of 1.00 revolution per 8.00 s. Estimate the mer
son4ous [18]

Solution :

Given data :

Mass of the merry-go-round, m= 1640 kg

Radius of the merry-go-round, r = 7.50 m

Angular speed, $\omega = \frac{1}{8}$  rev/sec

                             $=\frac{2 \pi \times 7.5}{8}$  rad/sec

                              = 5.89 rad/sec

Therefore, force required,

$F=m.\omega^2.r$

   $$=1640 \times (5.89)^2 \times 7.5  

   = 427126.9 N

Thus, the net work done for the acceleration is given by :

W = F x r

   = 427126.9 x 7.5

   = 3,203,451.75 J

6 0
3 years ago
How much energy is needed to generate 0.71 x 10-16 kg of mass?
AleksAgata [21]

Answer:

6.39 J of energy is needed to generate 0.71 * 10⁻¹⁶ kg mass

Explanation:

According to the Equation: E = mc²

where the mass, m = 0.71 * 10⁻¹⁶ kg

the speed of light, c = 3 * 10⁸ m/s

The amount of energy needed to generate a mass of 0.71 * 10⁻¹⁶ kg is calculated as follows:

E = (0.71 * 10⁻¹⁶) (3 * 10⁸)²

E = 0.71 * 10⁻¹⁶ * 9 * 10¹⁶

E = 0.71 * 9

E = 6.39 J

6 0
3 years ago
at a temperature of 10 c,700 ml of hydrogen is collected. if this gas is put into a 1000 ml container what will its new temperat
erastovalidia [21]

Answer:

14.3°C

Explanation:

Find the ratio of 10°C : 700ml then use the same ratio to 1000ml.

Have a great day <3

4 0
3 years ago
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