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2 years ago

My car engine can generate 3000 Newtons of force and the car masses 1500 kg. How fast can the sports car accelerate?

Physics

1 answer:

xeze [42]2 years ago

8 0

Answer:

The sports Car can accelerate at 2 m/s².

Explanation:

Force:

Force is the push or pull on an object with mass that causes it to change velocity or to accelerate.

Force represents as a vector, which means it has both magnitude and direction.

Given:

Mass of car = 1500 kg

Force = 3000 Newtons

To Find:

Acceleration, = ?

Solution:

Formula:

$Force = Mass\times Acceleration\\F= ma\\3000 = 1500\times Acceleration\\Acceleration = \frac{3000}{1500} \\Acceleration = 2\ m/s^{2}$

Therefore, the sports Car can accelerate at 2 m/s².

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I need help, please!

marta [7]

NO. it is not balanced

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2 years ago

A weight lifter is trying to do a bicep curl with a weight of 300 N. At the "sticking point", the moment arm of this weight is 3

lesantik [10]

Answer:

The weight lifter would not get past this sticking point.

Explanation:

Generally torque applied on the weight is mathematically represented as

T = F z

To obtain Elbow torque we substitute 4000 N for F (the force ) and 2cm $= \frac{2}{100} = 0.02m$ for z the perpendicular distance

So Elbow Torque is $T_e= 4000 * 0.02$

$= 80Nm$

To obtain the torque required we substitute 300 N for F and 30cm $=\frac{30}{100} = 0.3 m$

So the Required Torque is $T_R = 300 *0.3$

$=90Nm$

Now since $T_e < T_R$ it mean that the weight lifter would not get past this sticking point

7 0

2 years ago

A balloon is launched at 2.5 m every second, how far did it travel in 10 seconds?

Elina [12.6K]

Answer:

25 meters

Explanation:

1 sec is 2.5, 1x10 so 2.5x10=25

7 0

2 years ago

Show that the Mass spring system executes simple harmonic motion(SHM)?

murzikaleks [220]

Explanation:

Show that the motion of a mass attached to the end of a spring is SHM

Consider a mass "m" attached to the end of an elastic spring. The other end of the spring is fixed

at the a firm support as shown in figure "a". The whole system is placed on a smooth horizontal surface.

If we displace the mass 'm' from its mean position 'O' to point "a" by applying an external force, it is displaced by '+x' to its right, there will be elastic restring force on the mass equal to F in the left side which is applied by the spring.

According to "Hook's Law

F = - Kx ---- (1)

Negative sign indicates that the elastic restoring force is opposite to the displacement.

Where K= Spring Constant

If we release mass 'm' at point 'a', it moves forward to ' O'. At point ' O' it will not stop but moves forward towards point "b" due to inertia and covers the same displacement -x. At point 'b' once again elastic restoring force 'F' acts upon it but now in the right side. In this way it continues its motion

from a to b and then b to a.

According to Newton's 2nd law of motion, force 'F' produces acceleration 'a' in the body which is given by

F = ma ---- (2)

Comparing equation (1) & (2)

ma = -kx

Here k/m is constant term, therefore ,

a = - (Constant)x

a a -x

This relation indicates that the acceleration of body attached to the end elastic spring is directly proportional to its displacement. Therefore its motion is Simple Harmonic Motion.

5 0

2 years ago

A stunt woman attempts to swing from the roof of a m 24 high building to the bottom of an identical building using a m 24 rope,

MakcuM [25]

Answer:

Height from ground is 8 m where string will break

Explanation:

Let the string makes some angle with the vertical after some instant of time

So here we have

$T - mg cos\theta = \frac{mv^2}{R}$