All categories

3 years ago

My car engine can generate 3000 Newtons of force and the car masses 1500 kg. How fast can the sports car accelerate?

Physics

1 answer:

xeze [42]3 years ago

8 0

Answer:

The sports Car can accelerate at 2 m/s².

Explanation:

Force:

Force is the push or pull on an object with mass that causes it to change velocity or to accelerate.

Force represents as a vector, which means it has both magnitude and direction.

Given:

Mass of car = 1500 kg

Force = 3000 Newtons

To Find:

Acceleration, = ?

Solution:

Formula:

$Force = Mass\times Acceleration\\F= ma\\3000 = 1500\times Acceleration\\Acceleration = \frac{3000}{1500} \\Acceleration = 2\ m/s^{2}$

Therefore, the sports Car can accelerate at 2 m/s².

You might be interested in

You are riding a bicycle at 20 m/s at 10:00 am. At 10:01 am, you notice that you are traveling at 40 m/s. You are headed W. What

Juliette [100K]

Answer:

20m/s^2

Explanation:

Acceleration=Change in velocity/time taken for change

40-20/1

20m/s^2

7 0

3 years ago

a 5.0 kg ball is dropped from a 2.5 m high window. what is the velocity of the ball just before it hits the ground?

julsineya [31]

Answer:

Approximately $7.0\; \rm m \cdot s^{-1}$ .

Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.

Explanation:

Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant $g = 9.81 \; \rm m \cdot s^{-2}$ near the surface of the earth.

For an object that is accelerating constantly,

$v^2 - u^2 = 2\, a \, x$ ,

where

$u$ is the initial velocity of the object,
$v$ is the final velocity of the object.
$a$ is its acceleration, and
$x$ is its displacement.

In this case, $x$ is the same as the change in the ball's height: $x = 2.5\; \rm m$ . By assumption, this ball was dropped with no initial velocity. As a result, $u = 0$ . Since the ball is accelerating due to gravity, $a = 9.81\; \rm m \cdot s^{-2}$ .

$v^2 - u^2 = 2\, g \cdot h$ .

In this case, $v$ would be the velocity of the ball just before it hits the ground. Solve for

$v^2 = 2\, a\, x + u^2$ .

$\begin{aligned}v &= \sqrt{2\, a\, x + u^2} \\ &= \sqrt{2\times 9.81 \times 2.5 + 0} \\ &\approx 7.0\; \rm m\cdot s^{-1}\end{aligned}$ .

3 0

3 years ago

Five scientist who travelled to space

Masja [62]

Answer:

The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...

Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...

Nicolaus Copernicus. Public Domain. ...

Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...

Galileo Galilei. NASA

6 0

3 years ago

High mass stars are more massive produce more energy burn brighter and have shorter life cycle than low mass stars

Zarrin [17]

Yes, they do all of those things.

5 0

3 years ago

A uranium nucleus is traveling at 0.94 c in the positive direction relative to the laboratory when it suddenly splits into two p

Anettt [7]

Answer:

A u = 0.36c B u = 0.961c

Explanation:

In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains

u ’= (u-v) / (1- uv / c²)

Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory

The data give is u ’= 0.43c and the initial core velocity v = 0.94c

Let's clear the speed with respect to the observer (u)

u’ (1- u v / c²) = u -v

u + u ’uv / c² = v - u’

u (1 + u ’v / c²) = v - u’

u = (v-u ’) / (1+ u’ v / c²)

Let's calculate

u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)

u = 0.51c / (1 + 0.4042)

u = 0.36c

We repeat the calculation for the other piece

In this case u ’= - 0.35c

We calculate

u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)

u = 1.29c / (1- 0.329)

u = 0.961c

6 0

3 years ago

My car engine can generate 3000 Newtons of force and the car masses 1500 kg. How fast can the sports car accelerate?​

My car engine can generate 3000 Newtons of force and the car masses 1500 kg. How fast can the sports car accelerate?