Convection<span> is </span>heat transfer<span> by mass motion of a fluid such as air or water when the </span>heated<span> fluid is caused to move away from the source of </span>heat<span>, carrying energy with it. </span>
<em><u>Given</u></em><em> </em> :
- <em>O</em><em>bject </em><em>position</em><em> </em>( u ) = - 36 cm
- <em>focal</em><em> </em><em>length</em><em> </em>( f ) = - 16 cm
- <em>image position</em><em> </em>( v ) = ?
now, we know
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So<em><u>, image position</u></em> = 28.8 cm, at same side of object .
Answer:
Ep= 3.8 10⁵ N/C
Explanation:
Conceptual analysis
The electric field at a point P due to a point charge is calculated as follows:
E = k*q/d²
E: Electric field in N/C
q: charge in Newtons (N)
k: electric constant in N*m²/C²
d: distance from charge q to point P in meters (m)
Equivalence
1nC= 10⁻⁹C
1cm= 10⁻²m
Data
k= 9*10⁹ N*m²/C²
q₁ =+7.5 nC = +7.5*10⁻⁹C
q₂ = -2.0 nC = -2.0*10⁻⁹C
d₁ =d₂ = 1.5cm = 1.5 *10⁻²m = 0.015 m
Calculation of the electric fieldsat the midpoint (P) between the two charges
Look at the attached graphic:
E₁: Electric Field at point ;Due to charge q₁. As the charge q₁ is positive negative (q₁+), the field leaves the charge
.
E₂: Electric Field at point : Due to charge q₂. As the charge q₂ is negative (q₂-) ,the field enters the charge
E₁ = k*q₁/d₁² = 9*10⁹ *7.5 *10⁻⁹/ ( 0.015 )² = 3*10⁵ N/C
E₂ = k*q₂/d₂²= 9*10⁹ *2*10⁻⁹/( 0.015 )² = 0.8*10⁵ N/C
The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.
Ep= E₁ + E₂
Ep= 3*10⁵ N/C
+ 0.8*10⁵ N/C
Ep= 3.8 10⁵ N/C
Answer:
The two positive electric charges repel each other. If a positive charge and a negative charge interact, their forces act in the same direction, from the positive to the negative charge. As a result opposite charges attract each other: The electric field and resulting forces produced by two electrical charges of opposite polarity.
Explanation:
Hope this helps!
-PBvibes
<3
Answer:
the girl must sit 2 cm from the pivot at the opposite end of the seesaw.
Explanation:
Given;
length of the seesaw, L = 4.0 m
weight of the boy, W₁ = 400 N
position of the boy from the pivot, d₁ = 1.5 m
weight of her sister, W₂ = 300 N
First, make a sketch of this information given;
0---0.5m---------------------Δ--------------------------4m
↓<--------1.5m-------> <---------x--------->↓
400 N 300N
Apply the principle of moment about the pivot, to determine the value of x;
Sum of anticlockwise moment = sum of clockwise moment
400(1.5) = 300(x)
600 = 300x
x = 600/300
x = 2 cm
Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.