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3 years ago

At what point on the position-time graph shown is the object's instantaneous velocity greatest?

Physics

2 answers:

ioda3 years ago

7 0

I'm probably going to have to say C. E as it seems the steepest right around there. If I'm wrong on that, it has to be B. B

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

The velocity is greatest at B.

Explanation:

The velocity or instantaneous rate of change is represented on a sketch by the slope of the position curve at a point.

Analyzing the points.

The slope at points F or D have slope as 0, since we have flat tangent lines for them.

The slope for point E is negative, since the curve is decreasing.

The slope for point B is positive, since the curve is increasing at B.

Thus the greatest value of the velocity is point B due the curve is increasing at that point, and the velocity is represented by its slope.

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initial speed of the stuntman is given as

$v = 28 m/s$

angle of inclination is given as

$\theta = 15 degree$

now the components of the velocity is given as

$v_x = 28 cos15 = 27.04 m/s$

$v_y = 28 sin15 = 7.25 m/s$

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

$\delta y = -25 m$

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by solving above equation we have

$t = 3.12 s$

Now in the above interval of time the horizontal distance moved by it is given by

$d_x = v_x * t$

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since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

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