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ipn [44]
3 years ago
13

At what point on the position-time graph shown is the object's instantaneous velocity greatest?

Physics
2 answers:
ioda3 years ago
7 0

I'm probably going to have to say C. E as it seems the steepest right around there. If I'm wrong on that, it has to be B. B

gizmo_the_mogwai [7]3 years ago
7 0

Answer:

The velocity is greatest at B.

Explanation:

The velocity or instantaneous rate of change is represented on a sketch by the slope of the position curve at a point.

Analyzing the points.

The slope at points F or D have slope as 0, since we have flat tangent lines for them.

The slope for point E is negative, since the curve is decreasing.

The slope for point B is positive, since the curve is increasing at B.

Thus the greatest value of the velocity is point B due the curve is increasing at that point, and the velocity is represented by its slope.

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A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?
Advocard [28]

Answer:

v=697.2km/h

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

V=\frac{d}{t}

The distance is clearly 1743 km and the time is:

t=2h+30min*\frac{1h}{60min} =2.5h

Thus, the velocity turns out:

v=\frac{1743km}{2.5h}\\ \\v=697.2km/h

Which is a typical velocity for a plane to allow it be stable when flying.

Best regards.

5 0
3 years ago
If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain u
zaharov [31]

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

6 0
3 years ago
Read 2 more answers
A golf club hits a stationary 0.05kg golf ball with and average force of 5.0 x 10^3 newtons accelerating the ball at 44 meters p
maxonik [38]

Answer: The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds

Explanation:

Force applied on the golf ball = 5.0\times 10^3 N

Mass of the ball = 0.05 kg

Velocity with which ball is accelerating = 44 m/s

Time period over which forece applied = t

f=ma=\frac{m\times v}{t}

t=\frac{0.05 kg\times 44m/s}{5.0\times 10^3 N}=4.4\times 10^{-4} seconds

Impulse=(force)\times (time)=f\times t = 5.0\times 10^3\times 4.4\times 10^{-4} seconds=2.2 Newton seconds

The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds

7 0
3 years ago
A race car starts from rest and accelerates uniformly to 69 mph in 4.5 s.
Marizza181 [45]
For this question we should apply
a = v^2 - u^2 by t
a = 69 - 0 by 4.5
a = 69 by 4.5
a = 15.33
a = 6.85 m/s^2

If the answer in option is near to answer then , you can mark it as correct.
.:. The acceleration is 6.9 m/s^2
5 0
2 years ago
What is the velocity (m/s) after 5 seconds of fall
gregori [183]
5 second fall starting at 0 m/s
ball strikes ground at a speed = 49 meters per second.
3 0
3 years ago
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