Question

Find the net charge of a system consisting of 206 electrons and 161 protons. Express your answer using two significant figures.

Answer 1

Answer:

-72\times 10^{-19}C[/tex]

Explanation:

Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge

Charge on 1 electron = $-1.6\times 10^{-19}C$

So charge on 206 electron $=-206\times 1.6\times 10^{-19}C$

Charge on 1 proton = $-1.6\times 10^{-19}C$

So charge on 161 electron $=-106\times 1.6\times 10^{-19}C$

So charge of the system = $(-206+161)\times 1.6\times 10^{-19}C$

$=-72\times 10^{-19}C$