Answer:
-3
Explanation:
= -3
So first make the improper fraction into a mixed number by taking out all the whole numbers from the numerator (3) and making sure the proper sign is in front of the answer (- 3) your remainder is the original numerator minus the product of the answer times the denominator: 24 - (3 • 7) = 24 - 21 = 3. Rewrite the mixed number.
Sort of. Both the best though
Answer:
one of the quantities is a constant multiple of the other, or equivalently if they have a constant ratio
Step-by-step explanation:
Answer:
I think its 2 times the original volume, im so sorry if im wrong!!
Step-by-step explanation:
Edit: I thought it was two but i guess it was 4, heres the real answer for people who were wondering, im so sorry!!
Answer: [B]: "contains one point" .
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Explanation:
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Given:
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x + y = 6 ;
x - y = 0 ;
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To solve for "x" ;
Consider the first equation:
x + y = 6 ;
subtract "y" from each side of the equation ; to isolate "x" on one side of the equation; and to solve for "x" ;
x + y - y = 6 - y ;
x = 6 - y ;
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Take the second equation:
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x - y = 0 ;
Solve for "x" ;
Add "y" to EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
x - y + y = 0 + y ;
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x = y
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x = 6 - y
Substitute "x" for "y" ;
x = 6 - x ;
Add "x" to Each side of the equation:
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x + x = 6 - x + x ;
2x = 6 ;
Now, divide EACH SIDE of the equation by "2" ; to isolate "x" on one side of the equation; and to solve for "x" ;
2x/2 = 6/2 ;
x = 3 .
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Now, since "x = 3" ; substitute "3" for "x" in both original equations; to see if we get the same value for "y" ;
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x + y = 6 ;
x - y = 0
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Start with the first equation:
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x + y = 6 ;
3 + y = 6 ;
Subtract "3" from each side of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
3 + y - 3 = 6 - 3 ;
y = 3 .
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Now, continue with the second equation; {Substitute "3" for "x" to see the value we get for "y"} ;
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The second equation given is:
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x - y = 0 ;
Substitute "3" for "x" to solve for "y" ;
3 - y = 0 ;
Subtract "3" from EACH side of the equation:
3 - y - 3 = 0 - 3 ;
-1y = -3 ;
Divide EACH side of the equation by "-1" ; to isolate "y" on one side of the equation; and to solve for "y" ;
-1y/-1 = -3/-1 ;
y = 3 .
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So, for both equations, we have one value: x = 3, y = 3; or: write as:
"(3, 3)" ; { which is: "one single point" ; which is: Answer choice: [B] } .
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