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irga5000 [103]
3 years ago
11

I can be found in the 4th period on the periodic table.

Chemistry
1 answer:
Rainbow [258]3 years ago
4 0

Vanadium (V)

Vanadium is the only one in the 4th period here so

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Question 1<br>Which of the following is a false​
Bogdan [553]

Answer:

1.A 2.C 3.B

4. d

Explanation:

6 0
3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
katovenus [111]

The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

<span>                                        = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0
3 years ago
Read 2 more answers
Choose the correct statement.
Studentka2010 [4]

Answer:

B) Cations lose electrons having a charge of positive.

Explanation:

Hello there!

In this case, it is widely known that ions are classified as positive cations and negative anions, since the former is produced when a metal loses electrons and the latter when a nonmetal gains electrons; in such a way, the correct choice is:

B) Cations lose electrons having a charge of positive.

Best regards!

6 0
3 years ago
What can you say about the strength of the intermolecular forces in neon and argon based on the critical points of Ne and Ar? (c
algol13

Explanation:

Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.

It is known that gas phase of neon occurs at 50 K. As the boiling point of Ar is more than the boiling point of neon which means that there is strong intermolecular force of attraction between argon molecules as compared to neon molecules.

This is also because argon is larger in size. As a result, induced dipole-induced dipole forces leads to more strength in Ar as compared to Ne.

8 0
3 years ago
8. What is the oxidation number of N in KNO3?
Elza [17]

Answer:

The oxidation state of N in the KNO3 is +5

Explanation:

Oxidation rules:

1. Oxygen is -2, unless in peroxides.

2. Group 1 metals = +1

3. Group 2 metals = +2

4. If the molecule is neutral, all of the oxidation numbers have to add up to zero.

5. If the molecule is charged, all of the oxidation numbers have to add up to the charge of the molecule.  

So, the given formula represents the salt compound formula unit of potassium nitrate:  KNO3  

The formula unit is uncharged.

From our rules, we know that,

O = -2

And we can find K on the periodic table, in the first group, thus giving it a +1 charge. Now let's put it all together.

K = +1

N = x

O = -2

Let's take into account the number of atoms of each element we have and make an equation since we know everything has to add up to zero since the molecules are neutral.

+1 +x+3 (-2) = 0 (notice we multiplied 3 by -2 because in the formula we have 3 atoms of oxygen with -2 charge each)

x - 5 = 0

x = 5

Therefore, the oxidation number of N in KNO3 is +5.

5 0
3 years ago
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