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avanturin [10]
3 years ago
12

A gas with a volume of 8 L at a temperature of 473K is switched to a new container with a temperature of 350K. If the pressure r

emains constant what is the new volume?
5.92L
10.81L
3.08L
20.78L
Chemistry
1 answer:
Digiron [165]3 years ago
5 0

Answer:

The new  volume is 5.92 L,  which is approximately 6 L

Explanation:

As the gas temperature increases, the molecules move faster and take less time to reach the walls of the container. This means that the number of crashes per unit of time will be greater. That is, there will be an increase (for an instant) in the pressure inside the container and the volume will increase.

So Charles's Law is one of the gas laws that relates the volume and temperature of a certain amount of gas at constant pressure and says that:

  • If the temperature increases the volume increases
  • If the temperature decreases the volume decreases

Mathematically this is expressed by:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas, this law is expressed by:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1: 8 L
  • T1: 473 K
  • V2: ?
  • T2: 350 K

Replacing:

\frac{8 L}{473K} =\frac{V2}{350K}

Solving:

V2=350K*\frac{8L}{473K}

V2=5.92 L

<u><em>The new  volume is 5.92 L,  which is approximately 6 L</em></u>

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As we know,
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4 0
3 years ago
Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

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5 0
3 years ago
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Answer:

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

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                                  1                  :             3

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3 0
3 years ago
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