Two Consecutive Odd Numbers: D, D+2
(D+2) + 2D = 4D - 27
D + 2 + 2D = 4D - 27
3D + 2 = 4D - 27
3D + 29 = 4D
29 = D
Two Consecutive Odd Numbers are 29, 31
Check. . 31 + 2(29) = 4(29) - 27
..................31 + 58 = 116 - 27
.................89 = 89 ..... CORRECT!
Answer:
9.72
Step-by-step explanation:
s1 = 10.6383 ; s2 = 5.21289
x1 = 147.583 ; x2 = 136.417
n1 = 12 ; n2 = 12
df1 = n1 - 1 = 12 - 1 = 11
df2 = n2 - 1 = 12 - 1 = 11
The test statistic :
(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]
Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)
Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926
Test statistic, T* :
(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))
11.166 / √(7.926 * (1/6)
11.166 / √1.321
11.166 / 1.1493476
T* = 9.7150766
Test statistic = 9.72
Use long multiplication to evaluate.
225000000
hope it helps you pls mark me brainliest pls.
