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ArbitrLikvidat [17]
3 years ago
6

Convert the following word equations into formula equations by changing element and compound names into chemical formulas.

Chemistry
1 answer:
almond37 [142]3 years ago
3 0

Answer:

Na + O.2 = NaO.2 whereas Cu + AgNo3 = Cu.2No.3 +AG

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2. When water droplets in a cloud combine, become too heavy, and fall to the ground, you
irga5000 [103]

Answer: precipitation

5 0
3 years ago
Which quantity is equivalent to 50 kilocalories
Tanya [424]

I believe this problem have these following choices:

5,000 cal

0.05 cal

5 x 10^3 cal

5 x 10 ^4 cal

 

<span>Now 1 kilocalorie  = 1000 calories, therefore:</span>

 

50 kilocalories * (1000 calories / 1 kilocalorie) = 50,000 calories

 

 

Since there are 4 zeroes, so the scientific notation is:

 

5 x 10 ^4 cal         (ANSWER)

7 0
4 years ago
N₂(g) + 3H₂(g) → 2NH3(g)
Anna71 [15]

Answer:

93.5 moles N₂

Explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

8 0
2 years ago
How does the number of products in a synthesis reaction compare with the number of reactants?
bearhunter [10]
Its a)the no. of products are greater than the no. of reactants
5 0
4 years ago
Read 2 more answers
If you had excess chlorine, how many moles of aluminum chloride could be produced from 28.0 g of aluminum?
MaRussiya [10]

Answer:

1.04 moles of AlCl₃

Explanation:

Balanced Equation:  2Al°(s) + 3Cl₂(g) => 2AlCl₃(s)

Approach => convert given data (28 g Al°) to moles. The number of moles  AlCl₃ would equal the number of moles aluminum because coefficients for Aluminum and Aluminum Chloride are equal.

moles Al° = (28g)/(27g/mole ) = 1.04 mole Al°

From balanced equation moles AlCl₃ produced equals moles of Al° produced = 1.04 mole AlCl₃ because coefficients of Al° & AlCl₃.

5 0
4 years ago
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