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KonstantinChe [14]
2 years ago
6

Please help me what is the answer

Chemistry
1 answer:
Sladkaya [172]2 years ago
6 0

There are 20.8 moles of propanol

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.2 x 10⁵ molecules of propanol

\tt \dfrac{1.25\times 10^{25}}{6.02\times 10^{23}}=20.8~moles

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3 0
3 years ago
When an atom forms a positive ion (by losing electrons). Will the radius of an ion change from the radius of an atom? Explain wi
Colt1911 [192]

Radius of the positive ion will be smaller than the radius of its parent atom.

<h3>Explanation</h3>

Sodium Na has atomic number 11. A neutral Na atom has 11 electrons. It has

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Na tends to lose one electron. It would form an Na⁺ ion. The ion is positive and has ten electrons. It has

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Three of the main shells of Na contain electrons. Only two main shells contain electrons in Na⁺. The energy of the second main shell is higher than the first. It is more distant from the nucleus than the first electron shell. Similarly, the third main shell is further away from the nucleus than the second.

The outermost shell in Na is the third main shell. The outermost shell in Na⁺ is the second main shell. As a result, the outermost electrons in Na are further away from the nucleus that electrons in Na⁺. As a result, the radius of Na appears to be larger than that of Na⁺.

When an atom loses electrons to form a positive cation, it tends to lose all electron in its outermost shell (the valence shell). That will give the ion an octet, which is more stable than having one or two electrons left in the valence shell. The rule on Na shall still apply. The positive ion will have one less main shell; its radius shall be smaller than that of the parent atom.

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3 years ago
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