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3 years ago

Find the distance between the points (3, -8) and (8,4).

Mathematics

2 answers:

Sidana [21]3 years ago

6 0

Answer:

Step-by-step explanation:

Hello There!

We can calculate the distance between two points using the distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where the x and y values are derived from the coordinates in which you are trying to find the distance between

The points we need to find the distance between is (3,-8) and (8,4)

So we plug the x values and y values into the formula

$d=\sqrt{(8-3)^2+(4-(-8)^2} \\8-3=5\\4-(-8)=12\\d=\sqrt{5^2+12^2} \\5^2=25\\12^2=144\\144+25=169\\\sqrt{169} =13$

so we can conclude that the distance between the two points is 13 units

iogann1982 [59]3 years ago

5 0

Answer:

Step-by-step explanation:

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If the point 4,-1 is on the graph of f than f()=

Kryger [21]

Y = -1 ;
x= 4;

f (4)=-1;

5 0

3 years ago

The total operating cost to run the organic strawberry farm varies directly with its number of acres. What is the constant of va

kow [346]

Answer:

$16\ acres$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the number of acres

y ---> total operating costs

we have the ordered pair (20,551,520)

For x=20 acres, y=$551,520

<em>Find the value of the constant of proportionality k</em>

$k=\frac{y}{x}$

substitute the values of x and y

$k=\frac{551,520}{20}=\$27,576\ per\ acre$

The linear equation is equal to

$y=27,576x$

Find out how many acres are on a farm with a total operating cost of $441,216

For y=$441,216

substitute in the linear equation the value of y and solve for x

$441,216=27,576x$

$x=441,216/27,576$

$x=16\ acres$

5 0

4 years ago

Read 2 more answers

Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

oee [108]

The answer is $\frac{x^{4/3}y^{3}}{3}$ .

The fraction is: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }$
Let's rewrite it: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }$

Since $\frac{x^{a} }{x^{b}} =x^{a-b}$ ,
then:
*** $\frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}$
*** $\frac{y^{-2} }{ y^{-5} }= y^{-2-(-5)} = y^{-2+5} = y^{3}$
______
$\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}$

8 0

3 years ago

What’s the formula for the sequence 13,27,41,55,....

alexdok [17]

Answer:

$t_{n}$ = 14n-1