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iVinArrow [24]
3 years ago
14

Question 7

Physics
2 answers:
Drupady [299]3 years ago
6 0
Power = energy/time=20/4=5.0
Dima020 [189]3 years ago
5 0

Answer:

the answer is B or 5 watts of power

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A ring of diameter 7.70 cm is fixed in place and carries a charge of 5.00 mC uniformly spread over its circumference. (a) How mu
MatroZZZ [7]

Answer:

3.974 Joule

Explanation:

Diameter of ring = 7.7 cm

a = Distance from the center = d/2 = 3.85 cm = 0.0385 m

Q = Charge = 5 mC

q = Charge to move = 3.4 mC

k = Coulomb constant = 9×10⁹ Nm²/C²

Work done will be equal to Potential energy when mass is at center

U=\frac{kQq}{a}\\\Rightarrow U=\frac{9\times 10^9\times 5\times 10^{-6}\times 3.4\times 10^{-6}}{0.0385}=3.974\ J

∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule

4 0
3 years ago
Read 2 more answers
Rohith has been jogging to the bus stop for 2.0 minutes at 3.5 m/s when he looks at
nikdorinn [45]
Multiply these numbers and there’s your answer
6 0
3 years ago
If a ball is dropped from a height​ (H) its velocity will increase until it hits the ground​ (assuming that aerodynamic drag due
mario62 [17]

Answer:

9.801 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 39 ft/s

s = Displacement = 720 cm = 7.2 m

a = Acceleration

Converting to m/s

39\ ft/s=\frac{39}{3.281}=11.88\ m/s

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{11.88^2-0^2}{2\times 7.2}\\\Rightarrow a=9.801\ m/s^2

Acceleration of the ball is 9.801 m/s²

5 0
3 years ago
Need help asap if I fail this one I fail my grade so please tell me the right awser
bazaltina [42]
If you look up "distance vs time graph" you can pull up images on google and check them out. That's what I did and on the x-axis (horizontal line) it said "time." I'd go with time. 
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3 years ago
What would cause the pressure in a sealed container of gas to increase?
Whitepunk [10]
<span>a. The temperature increases.</span>
3 0
4 years ago
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