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Usimov [2.4K]
3 years ago
15

Give the importance of physics and technology to nation development.​

Physics
1 answer:
Lerok [7]3 years ago
8 0
Physics generates fundamental knowledge needed for the future technological advances that will continue to drive the economic engines of the world. Physics contributes to the technological infrastructure and provides trained personnel needed to take advantage of scientific advances and discoveries.
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Many particles, such as dust, are inhaled when people breathe. Which part of the respiratory system filters out the majority of
sergey [27]

Answer:

A: Nose

Explanation:

Because your nose has mucus covered hairs that catch some of the dust particles that you inhale.

8 0
3 years ago
Which of the following is not an application of Doppler technology?
Jlenok [28]
The correct answer to the question above is the third option; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology. If the Doppler technology is being used in medical field, it would be for the ultrasound of the heart and blood vessels for examination.
8 0
3 years ago
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A small metal bead, labeled A, has a charge of 26 nC . It is touched to metal bead B, initially neutral, so that the two beads s
adell [148]

Answer:

q_A=25.953\ \rm nC

q_B=0.047\ \rm nC

Explanation:

Given:

  • Total initial charge on bead A=26 nC
  • The distance between them=5 cm
  • Magnitude o the force between them =4.4\times10^{-4}

Using coulombs law the force between two charged particle is \dfrac{q_Aq_B}{4\pi \epsilon_0 r^2}

where r is the radial distance between them

According to question we have

4.4\times10^{-4}=\dfrac{q_Aq_B\times9\times10^9}{0.05^2}\\\\4.4\times10^{-4}=\dfrac{q_A(q_A-26\times10^{-9})\times9\times10^9}{0.05^2}\\q_A=25.953\ \rm nC\\q_B=0.047\ \rm nC

Hence the charge on two metal beads is calculated.

5 0
3 years ago
Two concentric current loops lie in the same plane. The smaller loop has a radius of 3.6 cm and a current of 12 A. The bigger lo
puteri [66]

Answer:

the radius of bigger loop = 6 cm

Explanation:

given,

two concentric current loops

smaller loop radius = 3.6 cm

]current in smaller loop = 12 A

current in the bigger loop = 20 A

magnetic field at the center of loop = 0

Radius of the bigger loop = ?

B_t = B_1 + B_2

0 = \dfrac{\mu_0I_1}{2R_1} +\dfrac{\mu_0I_2}{2R_2}

now, on solving

\dfrac{I_1}{R_1} = \dfrac{I_2}{R_2}

R_2 = I_2\dfrac{R_1}{I_1}

       = 20\times \dfrac{3.6}{12}

       = 6 cm

hence, the radius of bigger loop = 6 cm

7 0
3 years ago
How are stars important to the Milky Way
Elza [17]
Stars are a source of light and heat. They recycle all the matter, gas, and dust and process them into new material. They were created as a major driving force of evolution of the universe. 
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3 years ago
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