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ser-zykov [4K]
3 years ago
13

two balls each with with a mass of 0.5 kg, collide on a pool table. is the law of conservation of momentum satisfied in this col

lision
Physics
2 answers:
joja [24]3 years ago
7 0

Sample Response: Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s and the total momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.

Harrizon [31]3 years ago
4 0

Answer: yes, the law of conservation of momentum remains conserved always in a closed system.

Explanation:

Law of conservation of momentum states that initial momentum of the components in a closed system is equal to final momentum of the components. Thus, the total momentum remains constant i.e. conserved. The law of conservation of momentum hold true in all conditions - be it elastic collision or inelastic collision.

When two balls collide on pool table, the law of conservation of momentum is satisfied.

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A boxer hits a punching bag with a force. Describe what happens.
Anna35 [415]

The punching bag applies the same amount of force to the boxer’s hand.   (C)

5 0
3 years ago
The three ropes in the figure are tied to a small, very light ring. Two of these ropes are anchored to walls at right angles wit
netineya [11]
<span>Let t be the angle made by T3 with the x-axis.

 T3 * cos(t) = 20 N ---- (1)
 T3 * sin(t) = 60 N ----- (2)

 Square both equations and add:

T3^2 = 20^2 + 60^2 = 400 + 3600 = 4000
T3 = sqrt(4000) = 63.25 N
 
divide (2) by (1):
tan(t) = 60/20 = 3
t = arctan(3) = 71.57 degrees.

</span><span>Since the angle clockwise from the x-axis some books may call it a negative angle and say the angle is -71.57 degrees or round it to -71.6 or even -72 degrees.</span>
8 0
4 years ago
While on the moon, the Apollo astronauts enjoyed the effects of a gravity much smaller than that on
Ainat [17]

Answer:

1.628 \frac{m}{sec^{2} }

Explanation:

Anywhere in the universe, In a closed system, <u>Conservation of energy</u> is applicable.

In this case

Neil is initially on the surface of moon and has a velocity of 1.51 \frac{m}{sec} in upward direction.

⇒He has Kinetic energy= K_{i} = \frac{1}{2} m{v^{2} } J

But with respect to the surface of the moon,

where m=mass of moon

           v=velocity of Neil

He has Potential energy= P_{i}=0 J

At the highest point of his jump, his velocity =0

⇒ Kinetic energy=K_{f}=0 J

His Potential energy with respect to the surface of moon=P_{f}=m \times g\times h

where m=mass of moon

           g= gravitational acceleration on moon

           h=height from moon's surface

By Conservation Energy Principle

K_{i}+P_{i}=K_{f}+P_{f}

K_{i}+0=0+P_{f}

\frac{1}{2} m{v^{2} } = m \times g\times h

\frac{v^{2} }{2} =  g\times h

\frac{1.5^{2} }{2} J= g\times 0.7 m

⇒ g = \frac{1.14}{0.7} = 1.628 \frac{m}{sec^{2} }

8 0
3 years ago
A 15.0 kilogram cart initially traveling at 2.0 meters per second east accelerates uniformly at 0.75 meter per second squared ea
Montano1993 [528]

Answer:

Explanation:

Since this is not parabolic motion, it is one-dimensional motion. Very simple. What we are given is

mass: 15.0 kg

initial velocity: 2.0 m/s

acceleration: .75 m/s/s

time: 6.0 seconds

Since we are looking for final velocity, the equation we need for this is

v = v0 + at that says final velocity is equal to the initial velocity plus the acceleration of the object times how long it travels. We don't have a need for the mass here at all.

v=2.0\frac{m}{s}+.75\frac{m}{s^2}(6.0s)

Notice that one of the seconds labels to the right of the plus sign cancel out, leaving us with like units...which we HAVE to have if we want to add.

Simplifying a bit gives us

v = 2.0 m/s + 4.5 m/s so

v = 6.5 m/s

4 0
3 years ago
According to Galileo's pendulum theory, which factor determines the time taken to swing through one complete cycle?
Lesechka [4]
It depends on the length of the string and the speed its swinging at. If its short then it will reach the full swing in less of a time but if its a longer string then it would take a longer time to make a full swing.
6 0
3 years ago
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